Molecular formula of water molecule is H₂O.
Answer:
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The net force acting on the car is 65 N to the left
The net force acting on an object is simply defined as the resultant force acting on the object.
From the question given, we obtained the following data:
- Force applied to the right (Fᵣ) = 250 N
- Force applied to the left (Fₗ) = 315 N
- Net force (Fₙ) =?
The net force acting on the car can be obtained as follow:
Fₙ = Fₗ – Fᵣ
Fₙ = 315 – 250
<h3>Fₙ = 65 N to the left </h3>
Therefore, the net force acting on the car is 65 N to the left
Learn more on net force: brainly.com/question/19549734
Answer:
ax = -3.29[m/s²]
ay = -1.9[m/s²]
Explanation:
We must remember that acceleration is a vector and therefore has magnitude and direction.
In this case, it is accelerating downwards, therefore for a greater understanding we will make a diagram of said vector, this diagram is attached.
![a_{x}=-3.8*cos(30) = -3.29 [m/s^{2}]\\ a_{y}=-3.8*sin(30) = -1.9 [m/s^{2}]](https://tex.z-dn.net/?f=a_%7Bx%7D%3D-3.8%2Acos%2830%29%20%3D%20-3.29%20%5Bm%2Fs%5E%7B2%7D%5D%5C%5C%20a_%7By%7D%3D-3.8%2Asin%2830%29%20%3D%20-1.9%20%5Bm%2Fs%5E%7B2%7D%5D)
Answer:
q₃=5.3nC
Explanation:
First, we have to calculate the force exerted by the charges q₁ and q₂. To do this, we use the Coulomb's Law:

Since we know the net force, we can use this to calculate q₃. As q₁ is at the right side of q₃ and q₁ and q₃ have opposite signs, the force F₁₃ points to the right. In a similar way, as q₂ is at the left side of q₃, and q₂ and q₃ have equal signs, the force F₂₃ points to the right. That means that the resultant net force is the sum of these two forces:

In words, the value of q₃ must be 5.3nC.