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2 years ago

Give all possible, accurate, correct IUPAC names for the following compounds:

Chemistry

1 answer:

Viefleur [7K]2 years ago

6 0

Answer:

A. 4-ethyl-hex-3,5-dien-2-ol.

B. 2-chloro-3-methyl-5-tert-butylphenol.

Explanation:

Hello there!

In this case, according to the given problems, it is possible to apply the IUPAC rules to obtain the following names:

A. 4-ethyl-hex-3,5-dien-2-ol because we have an ethyl radical at the fourth carbon and the beginning of the parent chain is on the Me (CH3) because it is closest to first OH.

B. 2-chloro-3-methyl-5-tert-butylphenol: because we start at the alcohol and have a chlorine atom on the second carbon, a methyl radical on the third carbon, a tert-butyl on the fifth carbon and the parent chain is benzene which is phenol as an alcohol.

Regards!

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Which description is true of 0.02 M Ca(OH)2 if Ca(OH)2 completely dissociates in water? A. It’s a dilute strong acid. B. It’s a

Sphinxa [80]

Answer: B. It’s a dilute strong base.

Explanation:

1) Definition of acids and bases: as per Bronsted-Lowry model, an acid is a substance that donates hydrogen ions and a base is a substance that accepts hydrogen ions.

Ca(OH)₂ does not have hydrogen ions to donate, but it can accept hydrogen ions to form H₂O according to this equation: H⁺ + OH⁻ → H₂O.

Hence, Ca(OH)₂ is a base.

2) Definition of strong base: a strong base is a base that dissociates completely into metallic and hydroxide ions in aqueous solutions, while a weak base dissociates partially.

Hence, Ca(OH)₂ is a strong base.

3) Definition of dilute: it refers to a solution meaning that the substance is not pure and the concentration is low. Since, the solution the Ca(OH)₂ is 0.02 M means that it is dilute.

Therefore, we have found that the description of 0.02 M Ca(OH)₂ is that is is a dilute strong base (option B).

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3 years ago

Using the following equation for the combustion of octane calculate the heat associated with the formation of 100.0 g of carbon

natali 33 [55]

Answer:

The right solution is "-602.69 KJ heat".

Explanation:

According to the question,

The 100.0 g of carbon dioxide:

= $\frac{100.0 \ g}{114.33\ g/mole}$

= $0.8747 \ moles$

We know that 16 moles of $CO_2$ formation associates with -11018 kJ of heat, then

0.8747 moles $CO_2$ formation associates with,

= $-\frac{0.8747}{16}\times 11018 \ KJ \ of \ heat$

= $-0.0547\times 11018$

= $-602.69 \ KJ \ heat$

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Elodia [21]

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Answer:

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Explanation:

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