Ask question

Ask question

All categories

3 years ago

7

What is the first step in nuclear fission? 60 POINTS BRAINLIEST

1 answer:

kobusy [5.1K]3 years ago

5 0

Answer:

<em><u>Energy is released.</u></em> In the first step, a uranium-235 atom absorbs a neutron, and splits into two new atoms (fission fragments), releasing three new neutrons and a large amount of binding energy.

You might be interested in

How is a radioactive element different from a stable element?

USPshnik [31]

A radioactive element has an unstable nucleus that emits particles in the form of alpha, beta, or gamma radiation. A stable element has a nucleus that does not emit such particles

8 0

3 years ago

Al calentar la mantequilla, esta se transforma en liquido, este cambio se denomina?

BlackZzzverrR [31]

Answer:

cambio fisico

Explanation:

4 0

3 years ago

How many liters of a 1.5 M solution can you make if you have .50 mol of KCl?

vaieri [72.5K]

Answer:

The answer to your question is 0.33 liters

Explanation:

Data

Volume = ?

Molarity = 1.5 M

number of moles = 0.5

Formula

$Molarity = \frac{number of moles }{volume}$

Solve for V

$Volume = \frac{number of moles}{molarity}$

Substitution

$Volume = \frac{0.5}{1.5}$

Simplification and result

Volume = 0.33 l

7 0

3 years ago

How would the freezing point of seawater compare with that of pure water

AleksAgata [21]

Given that seawater freezes at a lower temperature than pure water because of the salts dissolved in it.

8 0

3 years ago

A sample of O2 gas occupies a volume of 571 mL at 26 ºC. If pressure remains constant, what would be the new volume if the tempe

Vlad1618 [11]

Answer: The new volume at different given temperatures are as follows.

(a) 109.81 mL

(b) 768.65 mL

(c) 18052.38 mL

Explanation:

Given: $V_{1}$ = 571 mL, $T_{1} = 26^{o}C$

(a) $T_{2} = 5^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{5^{o}C}\\V_{2} = 109.81 mL$

(b) $T_{2} = 95^{o}F$

Convert degree Fahrenheit into degree Cesius as follows.

$(1^{o}F - 32) \times \frac{5}{9} = ^{o}C\\(95^{o}F - 32) \times \frac{5}{9} = 35^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{35^{o}C}\\V_{2} = 768.65 mL$

(c) $T_{2} = 1095 K = (1095 - 273)^{o}C = 822^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{822^{o}C}\\V_{2} = 18052.38 mL$

8 0

3 years ago