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eduard
3 years ago
10

How to find current in a series circuit

Physics
1 answer:
Alisiya [41]3 years ago
7 0
Divide the battery voltage by the sum of all the resistances in the series circuit. The quotient is the circuit current, in Amperes.
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What is a convex lens?​
Leona [35]

<em>The convex lens is a lens that converges rays of light that convey parallel to its principal axis (i.e. converges the incident rays towards the principal axis) which is relatively thick across the middle and thin at the lower and upper edges. The edges are curved outward rather than inward.</em>

6 0
3 years ago
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A particle moving on a circle has a velocity of 5 m/s and a normal acceleration of 10 m/s^2. What is the radius of the circle?
dybincka [34]

Answer:

Radius of the circle will be 2.5 m

Explanation:

We have given velocity of particle moving in the circle v = 5 m/sec

Acceleration of particle in the circle a=10m/sec^2

We have to find the radius of the circle

We know that acceleration is given by a=\frac{v^2}{r}

So 10=\frac{5^2}{r}

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So radius of the circle will be 2.5 m

3 0
3 years ago
Does air resistence decrease with speed
dybincka [34]

Answer:

yes

Explanation:

because when you slow down, the resistance slows with the speed.

3 0
3 years ago
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if a torque of 55.0 N/m is required and the largest force that can be exerted by you is 135 N what is th e length of the lever a
Whitepunk [10]

Answer:

r=0.41m

Explanation:

Torque is defined as the cross product between the position vector ( the lever arm vector connecting the origin to the point of force application) and the force vector.

\tau=r\times F

Due to the definition of cross product, the magnitude of the torque is given by:

\tau=rFsin\theta

Where \theta is the angle between the force and lever arm vectors. So, the length of the lever arm (r) is minimun when sin\theta is equal to one, solving for r:

r=\frac{\tau}{F}\\r=\frac{55\frac{N}{m}}{135N}\\r=0.41m

7 0
3 years ago
Which of the following is true of high clouds?
Wewaii [24]
I’m pretty sure it’s B
3 0
2 years ago
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