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vladimir1956 [14]
2 years ago
6

NEED HELP ASAP PLEASE!

Physics
1 answer:
katrin [286]2 years ago
5 0

Answer:

Here is the solution hope it helps:)

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Which type of lever is steep road​
Anni [7]

Answer:

Third class lever

Explanation:

Third class lever

3 0
3 years ago
Nearly all physics problems will use the unit m/s^2 for acceleration. Explain why the seconds are squared. Why isn't the unit gi
sertanlavr [38]

Because acceleration is not speed, and speed is not acceleration. 
I'm sure you would not ask "Why isn't temperature given in acres,
as it is for area ?"  Speed and acceleration are different things, so
it's only natural that they have different units.


The magnitude (size) part of acceleration is:

         (how much speed changes) per second.

Are you speeding up ?
Are you traveling (2 meters per second) faster every second ?
Then your acceleration is

           (2 meters per second) per second .

When you write that phrase as an algebraic expression, it's

           (2 m/sec) / sec

and when you simplify that fraction, you get        2 m/sec² .


6 0
3 years ago
Water flows over a section of Niagara Falls at the rate of 1.1 × 106 kg/s and falls 50.0 m. How much power is generated by the f
Kryger [21]
<h3>Answer:</h3>

5.395 × 10^8 Watts

<h3>Explanation:</h3>

<u>We are given;</u>

  • Rate of flow is 1.1 × 10^6 kg/s
  • Distance is 50.0 m
  • Gravitational acceleration is 9.8 m/s²

We are required to calculate the power that is generated by the falling water

  • Power is the rate of work done
  • It is given by dividing the energy or work done by time
  • Power = Work done ÷ time

But; work done = Force × distance

Therefore;

Power = (F × d) ÷ time

The rate is 1.1 × 10^ 6 Kg/s

But, 1 kg = 9.81 N

Therefore, the rate is equivalent to 1.079 × 10^7 N/s

Thus,

Power = Rate (N/s) × distance

           = 1.079 × 10^7 N/s × 50.0 m

           = 5.395 × 10^8 Watts

The power generated from the falling water is 5.395 × 10^8 Watts

7 0
3 years ago
A particular X-ray photon has initial energy of 60 keV when it enters the body. This photon transmits through 30 cm of soft tiss
ankoles [38]

Answer:

E = 7.334 KeV

Explanation:

given,

initial energy = 60 keV

Δ x = 30 cm

E = E_0e^{-\mu \Delta x}

μ(for soft tissue) = 0.7 cm⁻¹ (taken from table)

E = E_0e^{-0.7\times 20}

         E = 60 × 0.1224

         E = 7.334 KeV

energy of x-ray photon after travelling through 30 cm soft tissue in body is E = 7.334 KeV

3 0
3 years ago
PLEASE ANSWER USING ALL MY POINTS FOR THIS NEED HELP (please answer all of them)
kipiarov [429]
4-C. ... 5-D. ... 6-A. ... 7-D. ... 8-C. ... 9-B. ... 10-D. It's really a joy and a delight that you've learned so much by posting all of these questions.
5 0
3 years ago
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