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shepuryov [24]
3 years ago
14

Todd drives west to work;54km on way in 1.5hours and then drives home in 2hrs. What is his velocity on the way to work? What is

his velocity on the way back home?

Chemistry
2 answers:
Nataly [62]3 years ago
7 0

Answer:

Explanation:

Velocity ​​is a physical quantity that expresses the relationship between the space traveled by an object, the time taken for it and its direction. In other words, velocity is associated with the change of position of a body over time.

Its unit in the International System of Units is the meter per second (\frac{m}{s}), but it can also be expressed in \frac{km}{hr}

So, in this case, the speed on the way to work will be:

velocity=\frac{54 km}{1.5 hours}

velocity= 36 \frac{km}{hr}

The velocity on the way back home will be:

velocity=\frac{54 km}{2 hours}

velocity= 27 \frac{km}{hr}

mafiozo [28]3 years ago
6 0

Explanation:

Below is an attachment containing the solution.

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andrey2020 [161]

Answer:

m O2 = 116,16 g

Explanation:

Ca(ClO3)2 ------------> CaCl2 + 3O2

n Ca(ClO3)2 = 250/207 = 1,21 mol

n O2 = 3n Ca(ClO3)2 = 1,21 * 3 = 3,63 mol

m O2 = 3,63 * 32 = 116,16 g

4 0
3 years ago
The following unbalanced equation illustrates the overall reaction by which the body utilizes glucose to produce energy: C6H12O6
s344n2d4d5 [400]

Answer:

the conversion factor is f= 6  mol of glucose/ mol of CO2

Explanation:

First we need to balance the equation:

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the conversion factor that allows to calculate the number of moles of CO2 based on moles of glucose is:

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f = 6 mol of CO2/ mol of glucose

for example, for 2 moles of glucose the number of moles of CO2 produced are

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3 years ago
A 1.25 g gas sample occupies 663 ml at 25∘ c and 1.00 atm. what is the molar mass of the gas?
lakkis [162]

Using ideal gas equation,  

P\times V=n\times R\times T

Here,  

P denotes pressure  

V denotes volume  

n denotes number of moles of gas  

R denotes gas constant  

T denotes temperature  

The values at STP will be:  

P=1 atm  

T=25 C+273 K =298.15K

V=663 ml=0.663L

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Mass of gas given=1.25 g g

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Number of moles of gas, n= \frac{Given mass of the gas}{Molar mass of the gas}

Number of moles of gas, n= \frac{1.25}{Molar mass of the gas}

Putting all the values in the above equation,

1\times 0.663=\frac{1.25}{Molar mass of the gas}\times 0.0821\times 298.15

Molar mass of the gas=46.15

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a sample of substance x that has a mass of 326.0 g releases 4325.8 cal when it freezes at its freezing point. if substance x has
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