Answer:
m O2 = 116,16 g
Explanation:
Ca(ClO3)2 ------------> CaCl2 + 3O2
n Ca(ClO3)2 = 250/207 = 1,21 mol
n O2 = 3n Ca(ClO3)2 = 1,21 * 3 = 3,63 mol
m O2 = 3,63 * 32 = 116,16 g
Answer:
the conversion factor is f= 6 mol of glucose/ mol of CO2
Explanation:
First we need to balance the equation:
C6H12O6(s) + O2(g) → CO2(g) + H2O(l) (unbalanced)
C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(l) (balanced)
the conversion factor that allows to calculate the number of moles of CO2 based on moles of glucose is:
f = stoichiometric coefficient of CO2 in balanced reaction / stoichiometric coefficient of glucose in balanced reaction
f = 6 moles of CO2 / 1 mol of glucose = 6 mol of glucose/ mol of CO2
f = 6 mol of CO2/ mol of glucose
for example, for 2 moles of glucose the number of moles of CO2 produced are
n CO2 = f * n gluc = 6 moles of CO2/mol of glucose * 2 moles of glucose= 12 moles of CO2
Using ideal gas equation,

Here,
P denotes pressure
V denotes volume
n denotes number of moles of gas
R denotes gas constant
T denotes temperature
The values at STP will be:
P=1 atm
T=25 C+273 K =298.15K
V=663 ml=0.663L
R=0.0821 atm L mol ⁻¹
Mass of gas given=1.25 g g
Molar mass of gas given=?


Putting all the values in the above equation,

Molar mass of the gas=46.15
1) Calculate the number of mols,n, of the substance
n = mass/ molar mass = 326.0 g / 58.45 g / mol = 5.577 moles
2) Calculate the molar heat of fusion as the total heat released by the sample divided by the number of moles
hf = heat released / n = 4325.8 cal / 5.577 moles = 775. 59 cal /mol
B) brings order to the elements. This is correct because elements are in order by highest atomic number.