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WITCHER [35]
3 years ago
11

The fact that an object placed in water displaces some of that water known as the "Ripple Effect"

Physics
2 answers:
Softa [21]3 years ago
8 0

Answer:

True

Hope this helps!

Explanation:

Igoryamba3 years ago
3 0
True, for sure. When anything hits a still body of water it, the water will move in all directions of the object hitting it.
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Work done by a gravitational force by lowering the bucket into the well is
katovenus [111]

Answer:

when we lower a bucket into a well to fetch water, the work done by gravity is positive since force and displacement are in the same direction.

Explanation:

3 0
3 years ago
A loaded ore car has a mass of 950 kg. and rolls on rails ofnegligible friction. It starts from rest ans is pulled up a mineshaf
stiks02 [169]

(a) 10241 W

In this situation, the car is moving at constant speed: this means that its acceleration along the direction parallel to the slope is zero, and so the net force along this direction is also zero.

The equation of the forces along the parallel direction is:

F - mg sin \theta = 0

where

F is the force applied to pull the car

m = 950 kg is the mass of the car

g=9.8 m/s^2 is the acceleration of gravity

\theta=30.0^{\circ} is the angle of the incline

Solving for F,

F=mg sin \theta = (950)(9.8)(sin 30.0^{\circ})=4655 N

Now we know that the car is moving at constant velocity of

v = 2.20 m/s

So we can find the power done by the motor during the constant speed phase as

P=Fv = (4655)(2.20)=10241 W

(b) 10624 W

The maximum power is provided during the phase of acceleration, because during this phase the force applied is maximum. The acceleration of the car can be found with the equation

v=u+at

where

v = 2.20 m/s is the final velocity

a is the acceleration

u = 0 is the initial velocity

t = 12.0 s is the time

Solving for a,

a=\frac{v-u}{t}=\frac{2.20-0}{12.0}=0.183 m/s^2

So now the equation of the forces along the direction parallel to the incline is

F - mg sin \theta = ma

And solving for F, we find the maximum force applied by the motor:

F=ma+mgsin \theta =(950)(0.183)+(950)(9.8)(sin 30^{\circ})=4829 N

The maximum power will be applied when the velocity is maximum, v = 2.20 m/s, and so it is:

P=Fv=(4829)(2.20)=10624 W

(c) 5.82\cdot 10^6 J

Due to the law of conservation of energy, the total energy transferred out of the motor by work must be equal to the gravitational potential energy gained by the car.

The change in potential energy of the car is:

\Delta U = mg \Delta h

where

m = 950 kg is the mass

g=9.8 m/s^2 is the acceleration of gravity

\Delta h is the change in height, which is

\Delta h = L sin 30^{\circ}

where L = 1250 m is the total distance covered.

Substituting, we find the energy transferred:

\Delta U = mg L sin \theta = (950)(9.8)(1250)(sin 30^{\circ})=5.82\cdot 10^6 J

8 0
3 years ago
When will an object sink in water, according to Archimedes' principle?​
inna [77]

Answer:

If the buoyant force is greater than the object's weight, the object will rise to the surface and float. If the buoyant force is less than the object's weight, the object will sink. If the buoyant force equals the object's weight, the object will remain suspended at that depth.

Explanation:

Not much explaining to do here!

7 0
3 years ago
On an ice skating rink, a girl of mass 50 kg stands stationary, face to face with a boy of mass 80 kg. The children push off of
andrey2020 [161]

Answer:

Pretty sure its -4.8%

Explanation:

Others asked this question and got this as an answer.

5 0
2 years ago
Read 2 more answers
If the pressure inside the cylinder increases to 1.6 atm, what is the final volume, in milliliters, of the cylinder?
Bess [88]

This is an incomplete question, here is a complete question.

The air in the cylinder with a piston has a volume of 220 mL and a pressure of 650 mmHg.

If the pressure inside the cylinder increases to 1.6 atm, what is the final volume, in milliliters, of the cylinder?

Answer : The final volume of the cylinder is, 117.6 mL

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure of gas = 650 mmHg = 0.855 atm   (1 atm = 760 mmHg)

P_2 = final pressure of gas = 1.6 atm

V_1 = initial volume of gas = 220 mL

V_2 = final volume of gas = ?

Now put all the given values in the above equation, we get:

0.855atm\times 220mL=1.6atm\times V_2

V_2=117.6mL

Therefore, the final volume of the cylinder is, 117.6 mL

8 0
3 years ago
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