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Blababa [14]
2 years ago
7

Given that the radius of the moon is roughly one-quarter that of the earth, find the mass of the moon in terms of the mass of th

e earth
Physics
1 answer:
MrRa [10]2 years ago
4 0

The mass of the moon is six times lower in terms of the mass of the earth because of the its lower size and shape.

<h3>What is the mass of the moon and earth?</h3>

The mass of the moon is 7.34767309 × 1022 kilograms while on the other hand, the mass of the earth is 5.97219 × 1024 kilograms. This difference is due to the lower radius of the moon as compared to earth.

So we can conclude that the mass of the moon is six times lower in terms of the mass of the earth because of the its lower size and shape.

Learn more about radius here: brainly.com/question/12908707

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When the Moon orbits Earth, what is the centripetal force?
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Earth's lithospheric plates interact at____.
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Explanation:

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3 years ago
Find the magnitude of this<br> vector:<br> 174 m<br> N<br> 188.4 m<br> HELP FAST
Tomtit [17]

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195.168 m

Explanation:

To find the magnitude of the vector you can use the Pythagorean Theorem since you have the height and base and the vector is really just the hypotenuse

Pythagorean Theorem:

a^2+b^2=c^2

Plug values in

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Add the two values

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Take the square root of both sides

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8 0
2 years ago
g A loop circuit has a resistance of R1 and a current of 2 A. The current is reduced to 1.4 A when an additional 2.2 Ω resistor
Mrrafil [7]

Answer:

R1 = 5.13 Ω

Explanation:

From Ohm's law,

V = IR............... Equation 1

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From the question,

I = 2 A, R = R1

Substitute into equation 1

V = 2R1................ Equation 2

When a resistance of 2.2Ω is added in series with R1,

assuming the voltage source remain constant

R = 2.2+R1,  and I = 1.4 A

V = 1.4(2.2+R1)................. Equation 3

Substitute the value of V into equation 3

2R1 = 1.4(2.2+R1)

2R1 = 3.08+1.4R1

2R1-1.4R1 = 3.08

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R1 = 3.08/0.6

R1 = 5.13 Ω

6 0
3 years ago
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