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Pepsi [2]
2 years ago
5

Answer the following questions.

Physics
1 answer:
OverLord2011 [107]2 years ago
8 0
For question one, you look at the specific heats of both land and water, the water has a higher specific heat, therefore, it takes more energy in order to raise it up another degree of Celsius. What specific heat also tells us is that it takes longer for the water to cool down, therefore, land heats up more during the day, but water will cool down slower at night.
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A tuning fork with a frequency of 404 Hertz is struck with a soft hammer. The fork is struck a second time by the
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Answer:

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Explanation:

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What is the term that describes the amount of water in a volume of air at a specific temperature compared to the amount of water
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Read 2 more answers
The first law of thermodynamics relates the heat transfer into or out of a system to the change of internal and the work done on
Artyom0805 [142]

Answer:

The heat transferred into the system is 183.5 J.

Explanation:

The first law of thermodynamics relates the heat transfer into or out of a system to the change of internal and the work done on the system, through the following equations.

ΔU = Q - W

where;

ΔU  is the change in internal energy

Q is the heat transfer into the system

W is the work done by the system

Given;

ΔU = 155 J

W = 28.5 J

Q = ?

155 = Q - 28.5

Q = 155 + 28.5

Q = 183.5 J

Therefore, the heat transferred into the system is 183.5 J.

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2 years ago
An electroscope is a device that has small gold foil strips suspended from a metal rod. A student brings a negatively charged ro
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3 years ago
The photon energies used in different types of medical x-ray imaging vary widely, depending upon the application. Single dental
pav-90 [236]

A) 5.0\cdot 10^{-11} m

The energy of an x-ray photon used for single dental x-rays is

E=25 keV = 25,000 eV \cdot (1.6\cdot 10^{-19} J/eV)=4\cdot 10^{-15} J

The energy of a photon is related to its wavelength by the equation

E=\frac{hc}{\lambda}

where

h=6.63\cdot 10^{-34}Js is the Planck constant

c=3\cdot 10^8 m/s is the speed of light

\lambda is the wavelength

Re-arranging the equation for the wavelength, we find

\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4\cdot 10^{-15}J}=5.0\cdot 10^{-11} m

B) 2.0\cdot 10^{-11} m

The energy of an x-ray photon used in microtomography is 2.5 times greater than the energy of the photon used in part A), so its energy is

E=2.5 \cdot (4\cdot 10^{-15}J)=1\cdot 10^{-14} J

And so, by using the same formula we used in part A), we can calculate the corresponding wavelength:

\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{1\cdot 10^{-14}J}=2.0\cdot 10^{-11} m

4 0
2 years ago
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