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3 years ago

Where can we found solar energy in britain

Physics

1 answer:

Mashcka [7]3 years ago

6 0

Regardless of whether solar ever truly turns into a noteworthy vitality source here in England is dubious. Up to this point, the UK solar industry had been going from solidarity to quality — in 2016, power delivered from solar power outperformed coal control out of the blue.

There is absolutely enough sunlight in the UK (we get around 60 percent of the sunlight got at the equator) to make putting resources into solar advantageous – as has been exhibited by the development of enormous scale solar tasks in Cornwall and Lincolnshire.

Be that as it may, since the legislature cut its help for the solar industry in 2015, the UK has seen an emotional fall in the rate of take off of solar PV boards. This foolhardy move has additionally activated a large number of occupation misfortunes in the solar industry.

Greenpeace is requiring the English government to desperately audit its help for the solar industry, for the atmosphere and for the effect it has had on the development of clean vitality industry occupations in the UK.

This is not copied and here is proof:

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Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. A stationary police car emits a sound of frequen

bixtya [17]

Answer:

a) The velocity of the car is 7.02 m/s and the car is approaching to the police car as the frequency of the police car is increasing.

b) The frequency is 1404.08 Hz

Explanation:

If the police car is a stationary source, the frequency is:

$f_{a} =(\frac{v+v_{c} }{v} )f_{s}$ (eq. 1)

fs = frequency of police car = 1200 Hz

fa = frequency of moving car as listener

v = speed of sound of air

vc = speed of moving car

If the police car is a stationary observer, the frequency is:

$f_{L} =f_{a} (\frac{v}{v-v_{c} } )=(\frac{v+v_{c} }{v-v_{c} } )f_{s}$ (eq. 2)

Now,

fL = frequecy police car receives

fs = frequency police car as observer

a) The velocity of car is from eq. 2:

$1250=1200(\frac{v+v_{c} }{v-v_{c} } )\\1250(v-v_{c} )=1200(v+v_{c} )\\v_{c} =\frac{50*344}{2450} =7.02m/s$

b) Substitute eq. 1 in eq. 2:

$f_{L} =(\frac{v+v_{p} }{v-v_{c} } )(\frac{v+v_{c} }{v-v_{p} } )f_{s} =(\frac{344+20}{344-7.02} )(\frac{344+7.02}{344-20} )*1200=1404.08Hz$

7 0

3 years ago

Tourists covered 255 km for a 4-hour ride by car and a 7-hour ride by train. what is the speed of the train, if it is 5 km/h gre

LekaFEV [45]

The distance covered by car is equal to (assuming it is moving by uniform motion) the product between the car's speed and the time of the car ride, 4 h:
$S_c = v_c t_c$
where
$v_c$ is the car's speed
$t_c = 4 h$ is the duration of the car ride

Similarly, the distance covered by train is equal to the product between the train's speed and the duration of the train ride, 7 h:
$S_t = v_t t_t$

The total distance covered is S=255 km, which is the sum of the distances covered by car and train:
$S=255 km = S_c + S_t$
which becomes
$255 = 4 v_c + 7 v_t$ (1)
we also know that the train speed is 5 km/h greater than the car's speed:
$v_t = 5 + v_c$ (2)

If we put (2) into (1), we find
$255 = 4v_c + 7(5+v_c)$
and if we solve it, we find
$v_c = 20 km/h$
$v_t = 25 km/h$

So, the car speed is 20 km/h and the train speed is 25 km/h.

4 0

3 years ago

For a snowboard jumper in the air, what force or forces will be most important for modeling the motion?

Reptile [31]

Answer: Gravitational force and drag force

Explanation:

For a snowboard jumper in the air, two forces would be acting. One in the downward direction- the gravitational pull and second in the opposite direction to the motion, the drag force due to air. If the snowboard jumper jumps in the air at a certain angle with the horizontal. The forces are written as the sum of vertical and horizontal components. Hence, for the modeling the motion, gravitational force and drag force are important,

4 0

2 years ago

Please help!!! 50 POINTS

taurus [48]

Answer:

The Energy Involved In A Reaction That Changes Methane Gas And Oxygen Into Carbon Dioxide And Water.

Explanation:

6 0

3 years ago

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Two automobiles of equal mass approach an intersection. One vehicle is traveling with velocity 14.0 m/s toward the east and the

Sergeeva-Olga [200]

Answer:

kqwwwwj

Explanation:

4 0

3 years ago