Answer:
145.52137 m/s
1.4 m
0.7 m
60.6339 Hz
121.2678 Hz
Explanation:
T = Tension = 120 N
= Linear density = 
m = Mass of wire = 6.8 g
L = Length of wire = 1.2 m
n = Number of loops
Velocity is given by
The speed of waves on the wire is 145.52137 m/s
Wavelength is given by
The wavelength of the waves that produces one-loop standing waves is 1.4 m
The wavelength of the waves that produces two-loop standing waves is 0.7 m
Frequency is given by
The frequency of the waves that produces one-loop standing waves is 60.6339 Hz
The frequency of the waves that produces two-loop standing waves is 121.2678 Hz
115.35 ft
Set the proportion up 37.50/105.50 = 41/x and solve for x
Answer:
B
Explanation:
From Newton's law of motion, we have:
V^2 = U^2 + 2gH
Where V and U are final and initial velocity respectively.
H is the height.
For the object to have a sustain a maximum height it means the final velocity of the object is zero.
By computing the height of the object sustain by A, we have:
0^2 = 2^2 -2×10×H
0= 4 -20H
4 = 20H;
H= 0.2m
For object B we have;
0^2 = 1^2 -2×10×H
0 = 1 -20H
H = 1/20= 0.05m
From computing the height sustain by both objects, we see object B is projected at a shorter height into atmosphere than A.
Hence object B will return to the ground first.
Answer:
W = 1.06 MJ
Explanation:
- We will use differential calculus to solve this problem.
- Make a differential volume of water in the tank with thickness dx. We see as we traverse up or down the differential volume of water the side length is always constant, hence, its always 8.
- As for the width of the part w we see that it varies as we move up and down the differential element. We will draw a rectangle whose base axis is x and vertical axis is y. we will find the equation of the slant line that comes out to be y = 0.5*x. And the width spans towards both of the sides its going to be 2*y = x.
- Now develop and expression of Force required:
F = p*V*g
F = 1000*(2*0.5*x*8*dx)*g
F = 78480*x*dx
- Now, the work done is given by:
W = F.s
- Where, s is the distance from top of hose to the differential volume:
s = (5 - x)
- We have the work as follows:
dW = 78400*x*(5-x)dx
- Now integrate the following express from 0 to 3 till the tank is empty:
W = 78400*(2.5*x^2 - (1/3)*x^3)
W = 78400*(2.5*3^2 - (1/3)*3^3)
W = 78400*13.5 = 1058400 J
Answer:
(1) An object that’s negatively charged has more electrons than protons.
(2) An object that’s positively charged has fewer electrons than protons.
(3) An object that’s not charged has the same number of electrons than protons.
Explanation :
Objects have three subatomic particles that are Electrons, protons, and neutrons.
Protons and neutrons are found in the nucleus and electrons rotate or move outside the nucleus. Naturally, protons are positively charged, neutrons have no charge, and electrons are negatively charged.
Therefore, an object that is negatively charged has more electrons than protons. An object that is not charged has the same number of electrons than protons. An object that is positively charged has fewer electrons than protons.
