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bagirrra123 [75]
3 years ago
10

Solve by factoring AKA zero product property method. If the equation has no real solutions, write no real solutions.

Mathematics
1 answer:
erica [24]3 years ago
7 0
Hello,

1)\\
x^2-5x+4=0\\
x^2-4x-x+4=0\\
x(x-4)-(x-4)=0\\
(x-4)(x-1)=0\\
Sol=\{1;4\}\\\\

2)\\
x^2+7x+12=0\\
x^2+3x+4x+12=0\\
x(x+3)+4(x+3)=0\\
(x+3)(x+4)=0\\
Sol=\{-4;-3\}


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