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2 years ago

13

What type of circuit is illustrated?

1 answer:

Reil [10]2 years ago

6 0

Answer:

I beleive its B

Explanation:

If not then A but I'm positive its B

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Radio waves are readily diffracted around buildings, whereas light waves are negligibly diffracted around buildings. This is bec

Tom [10]

Answer:

Radio waves have longer wavelength

Explanation:

Radio wave is an electromagnetic frequency that has the ability to travel through long distance. They have frequencies shuttling been the range of 10^4 hz and a frequency of 10^12 hz

Light wave is also called visible light. This is because it is visible to the naked eye, despite it being in the electromagnetic spectrum. It's frequency is usually between 4*10^-7 hz and a frequency of 7*10^-7 hz.

As can be seen from both, the radio waves length are quite far stronger than that of the light waves.

6 0

2 years ago

To a stationary, a bus moves south with a speed of 15 m/s. a man inside walks toward the front of the bus with a speed of 0.2 m/

marta [7]

It is 15.2 m/s South.

8 0

2 years ago

Read 2 more answers

What is done when an object is moved by a force

Flauer [41]

1). The object winds up in a different location.

2). Work is done.

7 0

3 years ago

The group of test subject that are NOT given the experimental treatment is called what?

-BARSIC- [3]

Answer:

The group that remains unaltered is called the control group.

5 0

3 years ago

The flywheel of a steam engine runs with a constant angular velocity of 190 rev/min. When steam is shut off, the friction of the

Ivanshal [37]

Answer:

(a) $\alpha = - 1.32\ rev/m^{2}$

(b) $\theta = 13674\ rev$

(c) $\alpha_{tan} = 8.75\times 10^{- 4}\ m/s^{2}$

(d) $a = 22.458\ m/s^{2}$

Solution:

As per the question:

Angular velocity, $\omega = 190\ rev/min$

Time taken by the wheel to stop, t = 2.4 h = $2.4\times 60 = 144\ min$

Distance from the axis, R = 38 cm = 0.38 m

Now,

(a) To calculate the constant angular velocity, suing Kinematic eqn for rotational motion:

$\omega' = \omega + \alpha t$

$omega'$ = final angular velocity

$\omega$ = initial angular velocity

$\alpha$ = angular acceleration

Now,

$0 = 190 + \alpha \times 144$

$\alpha = - 1.32\ rev/m^{2}$

Now,

(b) The no. of revolutions is given by:

$\omega'^{2} = \omega^{2} + 2\alpha \theta$

$0 = 190^{2} + 2\times (- 1.32) \theta$

$\theta = 13674\ rev$

(c) Tangential component does not depend on instantaneous angular velocity but depends on radius and angular acceleration:

$\alpha_{tan} = 0.38\times 1.32\times \frac{2\pi}{3600} = 8.75\times 10^{- 4}\ m/s^{2}$

(d) The radial acceleration is given by:

$\alpha_{R} = R\omega^{2} = 0.32(80\times \frac{2\pi}{60})^{2} = 22.45\ rad/s$

Linear acceleration is given by:

$a = \sqrt{\alpha_{R}^{2} + \alpha_{tan}^{2}}$

$a = \sqrt{22.45^{2} + (8.75\times 10^{- 4})^{2}} = 22.458\ m/s^{2}$

5 0

2 years ago