HELP WILL MARK BRAINLIEST!!

Neutrons can change the charge of an atom True False

IceJOKER [234]

Answer:

False. They can’t change the charge but they can change the mass

8 0

3 years ago

A projectile is fired straight up from ground level. After t seconds it's height is above the ground is h feet where h=-16t^2+14

Rainbow [258]

Plug in 288 for h, move it over to the right side and do the quadratic formula to solve for t. You will get 2 times, in between and including those times will give you the period it is at least 288 ft off the ground.

You can simplify this and not need to use the quadratic. 288=−16t^2+144t
Divide through by 16 getting
18=-t^2 + 9t
t^2−9t+18=0 Is what you would get after rearranging the equation Now you have something you can easily factor

5 0

3 years ago

Read 2 more answers

8.

GuDViN [60]

This ratio (Fnet/m) is sometimes called the gravitational field strength

and is expressed as 9.8 N/kg ⇒ answer D

Explanation:

The gravitational field strength at a point is:

The gravitational force exerted per unit mass placed at that point.
This means that the gravitational field strength, g is equal to the force experienced by a mass of 1 kg in that gravitational field
Gravitational field strength = Weight/mass
Its unit is Newton per kilogram
Gravitational field strength ≈ 9.8 N/kg

From the notes above

The ratio $\frac{F_{net}}{mass}$ = Gravitational field strength (g)

The answer is:

This ratio (Fnet/m) is sometimes called the gravitational field

strength and is expressed as 9.8 N/kg

Learn more:

You can learn more about gravitational field strength in brainly.com/question/6763771

LearnwithBrainly

5 0

3 years ago

If the discovery of oxygen wasn’t made in 1774, do you think it would have been discovered later on?

Scilla [17]

I don’t know sorry I’m new

8 0

2 years ago

A circular sector has an area of 64 in. squared. The radius of the circle is 8 in. What is the arc length of the sector?

Rom4ik [11]

Answer:

L = 16 [in]

Explanation:

In order to find the arch we must first find the angle that forms the circular sector, using the following formula:

$A = \frac{\alpha*r^{2} }{2} \\where:\\A= area = 64[in^{2}]\\r = radius = 8[in]\\\\\alpha = angle[rad]therefore\\\alpha =\frac{2*A}{r^{2} } \\\alpha =\frac{2*64}{8^{2} } \\\alpha =2[rad]$

Now using the following equation we can calculate the arc length

$L=\alpha *r\\L=2*8\\L=16[in]$

5 0

3 years ago