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Lapatulllka [165]
3 years ago
9

In a molecule of PCl3, 6 electrons will form

Chemistry
1 answer:
Igoryamba3 years ago
8 0

Answer:

polar covalent bonds

Explanation:

Phosphorus trichloride is a chemical compound of phosphorus and chlorine, having the chemical formula PCl 3. It has a trigonal pyramidal shape, owing to the lone pairs of electrons on the phosphorus atom.

Chlorine is more elctronegative than phosphorus . Phosphorus has a lone pair of electrons and every chlorine atom has three pairs of electrons . The molecule is not symmetrical as the shared electron pairs are closer to the chlorine atoms than the phosphorus atoms , the chlorine atoms are shifted towards one side of the center of the molecule , thus a net dipole effect is created. This is the reason why the molecule is polar .

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At the Henry's Law constant for carbon dioxide gas in water is . Calculate the mass in grams of gas that can be dissolved in of
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The question is incomplete, here is the complete question:

At 25°C Henry's Law constant for carbon dioxide gas in water is 0.031 M/atm . Calculate the mass in grams of gas that can be dissolved in 425. mL of water at 25°C and at a partial pressure of 2.92 atm. Round your answer to 2 significant digits.

<u>Answer:</u> The mass of carbon dioxide that can be dissolved is 1.7 grams

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{CO_2}=K_H\times p_{CO_2}

where,

K_H = Henry's constant = 0.031M/atm

C_{CO_2} = molar solubility of carbon dioxide gas

p_{CO_2} = partial pressure of carbon dioxide gas = 2.92 atm

Putting values in above equation, we get:

C_{CO_2}=0.031M/atm\times 2.92 atm\\\\C_{CO_2}=0.0905M

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of carbon dioxide = ? g

Molar mass of carbon dioxide = 44 g/mol

Molarity of solution = 0.0905mol/L

Volume of solution = 425 mL

Putting values in above equation, we get:

0.0905mol/L=\frac{\text{Mass of carbon dioxide}\times 1000}{44g/mol\times 425}\\\\\text{Mass of solute}=\frac{44\times 425\times 0.0905}{1000}=1.7g

Hence, the mass of carbon dioxide that can be dissolved is 1.7 grams

8 0
3 years ago
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