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3 years ago

8

According to Le Chatelier’s principle, what happens when the concentration of reactants is doubled in a chemical reaction that w

as in equilibrium?

2 answers:

Travka [436]3 years ago

6 0

Answer:

A) The equilibrium shifts to the right to favor the formation of products.

Explanation:

Usimov [2.4K]3 years ago

3 0

If more reactant is added, the equation will shift to the right in order to make more product (which will increase the products)

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What is the mass of oxygen in 300 grams of carbonic acid (H2CO3)

DENIUS [597]

mass of carbonic acid = 300g

molar mass of H2CO3 = 2H + C + 3 O

= 2 x 1.008+ 12.01 + 3 x 16

= 62.03g/mol

moles of H2CO3 = mass/Molar mass

= 300/62.03

= 4.8364 moles

1 mole H2CO3 has 3 moles Oxygen

4.8364 moles H2CO3 contains

= 3 x 4.8364 moles Oxygen = 14.509 moles Oxygen

moles = mass/Molar mass

mass of oxygen = moles x Molar mass of Oxygen

= 14.509 x 16

= 232.15g Oxygen

mass of oxygen in 300g of carbonic acid(H2CO3) = 232.15g

7 0

3 years ago

Q: What property of propane does Rodriguez change using the burner? Support your answer with evidence from the text.

UNO [17]

Answer:

The wind is starting to blow stronger, and when you’re riding in a basket under a hot air

balloon, just 400 feet above ground, that’s not necessarily a good thing. Keith Rodriguez looks

to the horizon and squints. He had planned to take off from Scioto Downs, a horse racetrack

south of Columbus, Ohio, fly a few miles north, and land his balloon in a barren cornfield next

to his pickup truck.

Then the wind changed. Instead of a light breeze from the south, now Rodriguez’s bright red

balloon is getting hit by stronger, colder winds from the west. He has plenty of propane fuel in

his tank—he probably could ride the wind halfway to Pennsylvania. But that would be

dangerous. Rodriguez’s choice of landing sites just became very limited. As the balloon

switches direction and floats east, everything below becomes a wide carpet of suburban

sprawl—big‐box stores, major highways, strip malls. Beyond the stores lie forests.

Explanation:

7 0

3 years ago

What is the difference between an atom in the ground state and an atom in an excited state? A. The atom in the ground state has

Marizza181 [45]

The correct option is C.

An atom can be either in the ground state or in an excited state. An atom is said to be in the ground state, if the total energy of its electron can not be lowered by moving one or more electrons into different orbitals. At the ground state, the electrons in the atom have the lowest energy possible and they are stable. On the other hand, an atom is said to be in an excited state, if the energy of its electrons can be lowered by transferring one or more electrons into different orbitals. An atom in an excited state has more energy and is less stable.

7 0

3 years ago

Read 2 more answers

HELP ASAP!! PLEASE !!

ZanzabumX [31]

Answer:

8,3, 7,7

Explanation:

6 0

2 years ago

Use this equation for the following problems: 2NaN3 --> 2Na+3N2

olchik [2.2K]

Answer:

1) 65.0

2) 16.434 L = 16434 mL.

Explanation:

<em>2NaN₃ → 2Na + 3N₂,</em>

It is clear from the balanced equation that 2.0 moles of NaN₃ are decomposed to 2.0 moles of Na and 3.0 moles of N₂.

<em>Q1: How many grams of NaN₃ are needed to make 23.6L of N₂? </em>

Density of N₂ = 0.92 g/L which means that every 1.0 L of N₂ contains 0.92 g of N₂.

Now, we can get the mass of N₂ in 23.6 L N₂ using cross multiplication:

1.0 L of N₂ contains → 0.92 g of N₂.

23.6 L of N₂ contains → ??? g of N₂.

∴ The mass of N₂ in 23.6 L of N₂ = (23.6 L)(0.92 g)/(1.0 L) = 21.712 g.

We can get the no. of moles of 23.6 L of N₂ (21.712 g) using the relation:

n = mass/molar mass = (21.712 g)/(28.0 g/mol) = 0.775 mol.

We can get the no. of moles of NaN₃ needed to produce 0.775 mol of N₂:

<em><u>using cross multiplication:</u></em>

2.0 moles of NaN₃ produce → 3.0 moles of N₂, from the balanced equation.

??? mol of NaN₃ produce → 0.775 moles of N₂.

∴ The no. of moles of NaN₃ needed = (2.0 mol)(0.775 mol)/(3.0 mol) = 0.517 mol.

Finally, we can get the grams of NaN₃ needed:

<em>mass = no. of moles x molar mass</em> = (0.517 mol)(65.0 g/mol) =<em> 33.6 g.</em>

<em />

<em>Q2: How many mL of N₂ result if 8.3 g Na are also produced?</em>

We need to get the no. of moles of 8.3 g Na using the relation:

n = mass/atomic mass = (8.3 g)/(22.98 g/mol) = 0.36 mol.

We can get the no. of moles of N₂ produced with 0.36 mol of Na:

<em><u>using cross multiplication:</u></em>

2.0 moles of Na produced with → 3.0 moles of N₂, from the balanced equation.

0.36 moles of Na produced with → ??? moles of N₂.

∴ The no. of moles of N₂ needed = (3.0 mol)(0.36 mol)/(2.0 mol) = 0.54 mol.

We can get the mass of 0.54 mol of N₂:

mass = no. of moles x molar mass = (0.54 mol)(28.0 g/mol) = 15.12 g.

Now, we can get the mL of 15.12 g of N₂:

<em><u>using cross multiplication:</u></em>

1.0 L of N₂ contains → 0.92 g of N₂, from density of N₂ = 0.92 g/L.

??? L of N₂ contains → 15.12 g of N₂.

<em>∴ The volume of N₂ result </em>= (1.0 L)(15.12 g)/(0.92 g) = <em>16.434 L = 16434 mL.</em>

4 0

3 years ago