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Vikki [24]
3 years ago
10

The world's largest wind turbine has blades that are 80 m long and makes 1 revolution every 5.7 seconds. What is the velocity fo

r one of the blades? (THIS IS PHYSICS, CIRCULAR MOTION)
Physics
1 answer:
Arturiano [62]3 years ago
7 0

Answer:

The velocity of the blades is 88.185 m/s.

Explanation:

Given;

length of the blade, r = 80 m

angular speed, ω = 1 rev per 5.7 seconds

The velocity of the blades is calculated by applying the following circular motion equation that relates linear velocity (V) and angular speed (ω);

V = \omega r\\\\V = (\frac{1 \ rev}{5.7 \ s} \times \frac{2  \pi \ rad}{ 1 \ rev} )(80 \ m)\\\\V = 88.185 \ m/s

Therefore, the velocity of the blades is 88.185 m/s.

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True or false<br> Hydrogen fuel cells generate electricity by combining hydrogen with oxygen.
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Answer:

The answer is: True.

Explanation:

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7 0
3 years ago
A 8.8 cm diameter circular loop of wire is in a 1.04 T magnetic field. The loop is removed from the field in 0.30 s . Assume tha
denis23 [38]

Answer:

0.021 V

Explanation:

The average induced emf (E) can be calculated usgin the Faraday's Law:

E = - \frac{N*\Delta \phi}{\Delta t}  

<u>Where:</u>

<em>N = is the number of turns = 1   </em>

<em>ΔΦ = ΔB*A                                            </em>

<em>Δt = is the time = 0.3 s   </em>

<em>A = is the loop of wire area = πr² = πd²/4 </em>

<em>ΔB: is the magnetic field = (0 - 1.04) T                     </em>

Hence the average induced emf is:

E = - \frac{\Delta B*A}{\Delta t} = - \frac{(0- 1.04 T) \pi (0.088 m)^{2}}{4*0.3 s} = 0.021 V                      

Therefore, the average induced emf is 0.021 V.

I hope it helps you!

8 0
3 years ago
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