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Vikki [24]
2 years ago
10

The world's largest wind turbine has blades that are 80 m long and makes 1 revolution every 5.7 seconds. What is the velocity fo

r one of the blades? (THIS IS PHYSICS, CIRCULAR MOTION)
Physics
1 answer:
Arturiano [62]2 years ago
7 0

Answer:

The velocity of the blades is 88.185 m/s.

Explanation:

Given;

length of the blade, r = 80 m

angular speed, ω = 1 rev per 5.7 seconds

The velocity of the blades is calculated by applying the following circular motion equation that relates linear velocity (V) and angular speed (ω);

V = \omega r\\\\V = (\frac{1 \ rev}{5.7 \ s} \times \frac{2  \pi \ rad}{ 1 \ rev} )(80 \ m)\\\\V = 88.185 \ m/s

Therefore, the velocity of the blades is 88.185 m/s.

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Mr. Jones's prescription calls for 1.04 tablets per day. Based on this information, how many tablets should Mr. Jones take per d
Serjik [45]

Due to the fact that no one can consume .04 of a tablet, we can round down this answer to 1. This means that Mr. Jones should take C- 1 tablet per day.

I hope I've helped! :)

7 0
2 years ago
A 1-kg rock is suspended from the tip of a horizontal meterstick at the 0-cm mark so that the meterstick barely balances like a
tigry1 [53]

Explanation:

Given that,

Mass if the rock, m = 1 kg

It is  suspended from the tip of a horizontal meter stick at the 0-cm mark so that the meter stick barely balances like a seesaw when its fulcrum is at the 12.5-cm mark.

We need to find the mass of the meter stick. The force acting by the stone is

F = 1 × 9.8 = 9.8 N

Let W be the weight of the meter stick. If the net torque is zero on the stick then the stick does not move and it remains in equilibrium condition. So, taking torque about the pivot.

9.8\times 12.5=W\times (50-12.5)\\\\W=\dfrac{9.8\times 12.5}{37.5}

W = 3.266 N

The mass of the meters stick is :

m=\dfrac{W}{g}\\\\m=\dfrac{3.266}{9.81}\\\\m=0.333\ kg

So, the mass of the meter stick is 0.333 kg.

5 0
3 years ago
_h2o2(aq)-_h2o(l) +o2(g)
zvonat [6]

Answer:

V02=9.78L

Explanation:

6 0
2 years ago
Two loudspeakers emit sound waves along the x-axis. A listener in front of both speakers hears a maximum sound intensity when sp
grandymaker [24]

Answer:

frequency of the sound = f = 1,030.3 Hz

phase difference = Φ = 229.09°

Explanation:

Step 1: Given data:

Xini = 0.540m

Xfin = 0.870m

v = 340m/s

Step 2: frequency of the sound (f)

f = v / λ

λ = Xfin - Xini = 0.870 - 0.540 = 0.33

f = 340 / 0.33

f = 1,030.3 Hz

Step 3: phase difference

phase difference = Φ

Φ = (2π/λ)*(Xini - λ) = (2π/0.33)* (0.540-0.33) = 19.04*0.21 = 3.9984

Φ = 3.9984 rad * (360°/2π rad)

Φ = 229.09°

Hope this helps!

5 0
3 years ago
4-7 Please! This is about scientific experiments.
ladessa [460]
Number 4 is c ,  number 5 is a  ,  number 6 is d and 7 is a 
8 0
3 years ago
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