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Vikki [24]
3 years ago
10

The world's largest wind turbine has blades that are 80 m long and makes 1 revolution every 5.7 seconds. What is the velocity fo

r one of the blades? (THIS IS PHYSICS, CIRCULAR MOTION)
Physics
1 answer:
Arturiano [62]3 years ago
7 0

Answer:

The velocity of the blades is 88.185 m/s.

Explanation:

Given;

length of the blade, r = 80 m

angular speed, ω = 1 rev per 5.7 seconds

The velocity of the blades is calculated by applying the following circular motion equation that relates linear velocity (V) and angular speed (ω);

V = \omega r\\\\V = (\frac{1 \ rev}{5.7 \ s} \times \frac{2  \pi \ rad}{ 1 \ rev} )(80 \ m)\\\\V = 88.185 \ m/s

Therefore, the velocity of the blades is 88.185 m/s.

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An object which is dropped from a certain height has zero (0) initial velocity.
gavmur [86]

Answer:

0 m/s

Explanation:

if an object is dropped we know the initial velocity is zero when in free fall

8 0
3 years ago
Bru this was a challenge......but
anygoal [31]

Answer:

Free points

Explanation:

6 0
3 years ago
Read 2 more answers
The current in the wires of a circuit is 120.0 milliAmps. If the voltage impressed across the ends of the circuit were doubled (
skad [1K]

Answer:

Its new current will be 240.0milliAmps

Explanation:

According to ohms law,

V = IR

V is the supply voltage in a circuit

I is the current

R is the resistance

If the current in the wires of a circuit is 120.0 milliAmps, the voltage will be:

V1 = 120R1

R1 = V1/120...(1)

If the voltage impressed across the ends of the circuit were doubled (with no change in its resistance),

V2 = 2V1

V2 = IR2

2V1 = IR2

R2 = 2V1/I ... (2)

Since there are no changes in resistance

R1 = R2

Equating 1 and 2, we have:

V1/120 = 2V1/I

1/120 = 2/I

Cross multiplying

I = 2×120

I = 240milliAmps

7 0
3 years ago
If the truck has a mass of 2,500 kilograms , what is its momentum ? (V=45m/s) Express your amswer
vlabodo [156]

Answer:

The answer is 2,500 * 45 = 112500kgm/s

6 0
2 years ago
Find the steady-state charge qp(t), and the steady-state current ip(t),in an LRC-series circuit when
Dmitry_Shevchenko [17]

(a) The value of the steady state charge in the circuit is 3 C.

(b) The steady-state current ,in an LRC-series circuit is 5.3 A.

<h3>Steady state charge</h3>

The value of the steady state charge in the circuit is calculated as follows;

Q = CV(max)

Q = 0.1 x 30

Q = 3 C

<h3>Steady state current in circuit</h3>

I = V/R

Vrms = 0.7071 x V(max)

Vrms = 0.7071 x 30

Vrms = 21.21 V

I = Vrms/R

I = 21.21/4

I = 5.3 A

Learn more about steady state current here: brainly.com/question/15726481

#SPJ1

4 0
2 years ago
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