Yes. The line is increasing. The flat line at the top of the graph is where there is not acceleration and the decreasing line is deceleration.
a) The kinetic energy (KE) of an object is expressed as the product of half of the mass (m) of the object and the square of its velocity (v²):

It is given:
v = 8.5 m/s
m = 91 kg
So:

b) We can calculate height by using the formula for potential energy (PE):
PE = m*g*h
In this case, h is eight, and PE is the same as KE:
PE = KE = 3,287.4 J
m = 91 kg
g = 9.81 m/s² - gravitational acceleration
h = ? - height
Now, let's replace those:
3,287.4= 91 * 9.81 * h
⇒ h = 3,287.4/(91*9.81) = 3,287.4/892.7 = 3.7 m
Answer:

Explanation:
Power is defined as the energy produced (E) per unit of time (t):

This means that the energy produced in the Sun each second (1 s), given the power
, is

Each p-p chain reaction produces an amount of energy of

in order to get the total number of p-p chain reactions per second, we need to divide the total energy produced per second by the energy produced by each reaction:

A) The resultant force is 30.4 N at 
B) The resultant force is 18.7 N at 
Explanation:
A)
In order to find the resultant of the two forces, we must resolve each force along the x- and y- direction, and then add the components along each direction to find the components of the resultant.
The two forces are:
at
above x-axis
at
above y-axis
Resolving each force:


So, the components of the resultant are:

And the magnitude of the resultant is:

And the direction is:

B)
In this case, the 15 N is applied in the opposite direction to the 20 N force. Therefore we need to re-calculate its components, keeping in mind that the angle of the 15 N force this time is

So we have:

So, the components of the resultant this time are:

And the magnitude is:

And the direction is:

Learn more about vector addition:
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Answer:
a = 0.1067 [m/s²]
Explanation:
In order to solve this problem, we must first draw a free body diagram with the forces acting on it.
a)
In the attached image we can find the free body diagram.
b)
The net force can be found by performing a sum of forces on the X-axis, these forces are seen in the free body diagram.
∑Fx = Fr
where:
Fr = resultant force [N] (units of Newtons)
![F_{r}=275+275-310\\F_{r}=240[N]](https://tex.z-dn.net/?f=F_%7Br%7D%3D275%2B275-310%5C%5CF_%7Br%7D%3D240%5BN%5D)
c)
Acceleration can be found by means of Newton's second law, which tells us that the sum of the forces in a body or the resulting force is equal to the product of mass by acceleration.
∑F = m*a
where:
m = mass = 2250 [kg]
a = acceleration [m/s²]
![240=2250*a\\a=0.1067[m/s^{2} ]](https://tex.z-dn.net/?f=240%3D2250%2Aa%5C%5Ca%3D0.1067%5Bm%2Fs%5E%7B2%7D%20%5D)