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ss7ja [257]
4 years ago
8

An object in uniform circular motion must be changing its speed in order move in a circular path

Physics
1 answer:
dlinn [17]4 years ago
5 0

No, that statement is false.

In uniform circular motion, the direction is constantly changing, but the speed is constant.

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Select all of the answers that apply.
galben [10]
<span>The answers are --

a
) wind direction
b) wind speed
e) intensity of precipitation
f) location of precipitation</span>
6 0
4 years ago
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If you had to choose one device to use with the battery, what would it be? Do you think such a battery could be invented
maw [93]

Answer:

a phone because it has longer lasting battery

Explanation:

6 0
3 years ago
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Unpolarized light passes through a vertical polarizing filter, emerging with an intensity I0. The light then passes through a ho
antiseptic1488 [7]

To solve this problem it is necessary to apply the concepts related to Malus' law. Malus' law indicates that the intensity of a linearly polarized ray of light that passes through a perfect analyzer with a vertical optical axis is equivalent to:

I = I_0 cos^2(\theta)

I_0 = Indicates the intensity of the light before passing through the Polarizer,

I = The resulting intensity, and

\theta = Indicates the angle between the axis of the analyzer and the polarization axis of the incident light.

There is 3 polarizer, then

For the exit of the first polarizer we have that the intensity is,

I_2 = I_0cos^2(45)

For the third polarizer then we have,

I_3 = I_2 cos^{2}(45)

Replacing with the first equation,

I_3 =  I_0cos^2(45)cos^{2}(45)

I_3 = I_0 (\frac{1}{2})(\frac{1}{2})

I_3 = I_0 \frac{1}{4}

Therefore the transmitted intensity now is \frac{1}{4} of the initial intensity.

5 0
4 years ago
A scientist compares two samples of colorless gas present at the beginning and end of a lab process. She wants to determine whet
kompoz [17]

Joseph Priestley was born in Yorkshire, the eldest son of a maker of wool cloth. His mother died after bearing six children in six years. Young Joseph was sent to live with his aunt, Sarah Priestley Keighley, until the age of 19. She often entertained Presbyterian clergy at her home, and Joseph gradually came to prefer their doctrines to the grimmer Calvinism of his father. Before long, he was encouraged to study for the ministry. And study, as it turned out, was something Joseph Priestley did very well.

Aside from what he learned in the local schools, he taught himself Latin, Greek, French, Italian, German and a smattering of Middle Eastern languages, along with mathematics and philosophy. This preparation would have been ideal for study at Oxford or Cambridge, but as a Dissenter (someone who was not a member of the Church of England) Priestley was barred from England's great universities. So he enrolled at Daventry Academy, a celebrated school for Dissenters, and was exempted from a year of classes because of his achievements.

After graduation, he supported himself, as he would for the rest of his life, by teaching, tutoring and preaching. His first full-time teaching position was at the Dissenting Academy in Warrington. (Although obviously brilliant, original, outspoken and, by one report, of "a gay and airy disposition," Priestley had an unpleasant voice and a sort of stammer. That he made a living through lectures and sermons is further evidence of his extraordinary nature.)


 https://www.acs.org/content/acs/en/education/whatischemistry/landmarks/josephpriestleyoxygen.html

8 0
3 years ago
Read 2 more answers
Calculate the energy (in eV/atom) for vacancy formation in some metal, M, given that the equilibrium number of vacancies at 296o
Schach [20]

Explanation:

The given data is as follows.

       Temperature of metal = 296^{o}C = (296 + 273) K

                                            = 569 K

     Density of the metal = 8.85 g/cm^{3} = 8.85 \times 10^{-6} g/m^{3}      (as 1 cm^{3} = 10^{-6} m^{3})

     Atomic mass = 51.40 g/mol

    Vacancies = 9.19 \times 10^{23} m^{-3}

Formula to calculate the number of atomic sites is as follows.

           n = \frac{\rho \times N_{A}}{\text{atomic weight}}

              = \frac{8.85 \times 10^{-6} \times 6.022 \times 10^{23}}{51.40 g/mol}

              = 1.036 \times 10^{17} atom/m^{3}

Now, we will calculate the energy as follows.

                E = -KT \times ln (\frac{\text{no. of vacancies}}{\text{no. of atomic sites}})

where,    K = 8.62 \times 10^{-5}

         E = -8.62 \times 10^{-5} \times 569 K \times ln (\frac{9.19 \times 10^{23}}{1.036 \times 10^{17} atom/m^{3}})

               = 78.46 eV/atom

Therefore, we can conclude that energy (in eV/atom) for vacancy formation in given metal, M, is 78.46 eV/atom.

6 0
4 years ago
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