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ss7ja [257]
4 years ago
8

An object in uniform circular motion must be changing its speed in order move in a circular path

Physics
1 answer:
dlinn [17]4 years ago
5 0

No, that statement is false.

In uniform circular motion, the direction is constantly changing, but the speed is constant.

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A ball is thrown at 60 degrees and lands in 18.5 seconds what is the velocity of the ball at the start
n200080 [17]

Answer:

the initial velocity of the ball is 104.67 m/s.

Explanation:

Given;

angle of projection, θ = 60⁰

time of flight, T = 18.5 s

let the initial velocity of the ball, = u

The time of flight is given as;

T = \frac{2u\times sin(\theta)}{g} \\\\2u\times sin(\theta) = Tg\\\\u = \frac{Tg}{2\times sin(\theta)} \\\\u = \frac{18.5 \times 9.8}{2\times sin(60^0)} \\\\u = 104.67 \ m/s

Therefore, the initial velocity of the ball is 104.67 m/s.

3 0
3 years ago
The coefficient of kinetic friction between an object and the surface upon which it is sliding is 0. 10. The mass of the object
lilavasa [31]

The force of friction is 78.4 N

What is force of friction?

Frictional force is the force created when two surfaces come into contact and slide against each other. it is given by the equation:

F_{f} = μ * F_{n}

where,

F_{f} = force of friction

μ = coefficient of friction

F_{n} = normal force

Given,

μ = 0.10,  m = 8.0 kg

We know,

F_{n} = mg

F_{n} = 8.0 * 9.8\\\\ F_{n} = 78.4 N

Subsituing the values in equation:

F_{f} = μ * F_{n}

F_{f} = 0.10 * 78.4 \\\\F_{f} = 7.84 N

The force of friction is 78.4 N.

To know more about force of friction, check out:

brainly.com/question/24386803

#SPJ4

4 0
1 year ago
2. A wire 4.00 m long and 6.00 mm in diameter has a resistance of 15.0 mΩ. A potential difference of 23.0 V is applied between t
Vikentia [17]

Answer:

Explanation:

a )

current in the wire = potential diff / resistance

= 23 / (15 x 10⁻³ )

= 1.533 x 10³ A .

b )

For resistance of a wire , the formula is

R = ρ L / S where ρ is specific resistance , L is length and S is cross sectional area of wire

putting the given values

15 x 10⁻³ = 4ρ / π x .003²

ρ = 106  x 10⁻⁹ ohm. m

= 10.6 x 10⁻⁸ ohm m

The metal wire appears to be platinum .

4 0
3 years ago
A 39-cm-long vertical spring has one end fixed on the floor. Placing a 2.2 kg physics textbook on the spring compresses it to a
Inessa05 [86]

Answer:

The spring constant is 215.6 N/m.

Explanation:

Given that,

Distance = 39 cm

Compresses length = 29 cm

Mass = 2.2 kg

We need to calculate the distance

Using formula of distance

x=l-l'

Put the value into the formula

x=39-29=10\ cm

We need to calculate the spring constant

Using formula of restoring force

F=kx

k=\dfrac{mg}{x}

Where, F = force

x = distance

Put the value into the formula

k=\dfrac{2.2\times9.8}{10\times10^{-2}}

k=215.6\ N/m

Hence, The spring constant is 215.6 N/m.

7 0
3 years ago
a ball of 5 kg is moving towards the wall at 6 m/s. after a while, it hits the wall and rebounds back at 4 m/s in the opposite d
iris [78.8K]

Answer:-50 J

Explanation:

3 0
3 years ago
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