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Georgia [21]
3 years ago
11

Anybody please help me in PHYSICS WAVE.

Physics
1 answer:
ruslelena [56]3 years ago
3 0
What is the question
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Prolonged exposure to movement in one direction ________ the motion detectors responsive to that direction. When the movement st
Readme [11.4K]

Answer:

fatigues; higher

Explanation:

5 0
3 years ago
A large turntable with radius 6.00 m rotates about a fixed vertical axis, making one revolution in 8.00 s. The moment of inertia
yanalaym [24]

Answer:

0.8024

Explanation:

From the given question; we can say that the angular momentum of the system is conserved if the net torque is  is zero.

So; I_o \omega _o = I_2 \omega_2

At the closest distance ; the friction is :

f_s = \mu_s (mg)

According to Newton's Law:

F = ma

F = mrω²

From conservation of momentum:

I_o \omega _o = I_2 \omega_2

\omega_2= \frac { I_o \omega _o}{ I_2 }

\omega_2=( \frac { I_1+ mr_o^2}{ I_1 + mr^2 })* \omega_o

However ; since the static friction is producing the centripetal force :

\mu_s (mg) = mr \omega_2^2

\mu _s = \frac{ \omega^2_2 *r }{g}

The coefficient of static friction between the bottoms of your feet and the surface of the turntable can now be calculated by using the formula :

\mu _s = \frac{ \omega^2_2 *r }{g}

=  ( \frac { I_1+ mr_o^2}{ I_1 + mr^2 })^2  * \frac{ \omega^2_o *r }{g}

= [\frac{1200+(73(6)^2)}{((1200)+(73)(3)^2)} ]^2*[\frac{(\frac{\pi}{4})^2(3)} {9.8}]

= 0.8024

4 0
3 years ago
A singly charged ion of 7Li (an isotope of lithium which lost only one electron) has a mass of 1.16 ×10^-26 kg. It is accelerate
MaRussiya [10]

Explanation:

It is given that,

Mass of lithium, m=1.16\times 10^{-26}\ kg

It is accelerated through a potential difference, V = 224 V

Uniform magnetic field, B = 0.724 T

Applying the conservation of energy as :

\dfrac{1}{2}mv^2=qV

v=\sqrt{\dfrac{2qV}{m}}

q is the charge on an electron

v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\ C\times 224\ V}{1.16\times 10^{-26}\ kg}}

v = 78608.58 m/s

v=7.86\times 10^4\ m/s

To find the radius of the ion's path in the magnetic field. The centripetal force is balanced by the magnetic force as :

qvB=\dfrac{mv^2}{r}

r=\dfrac{mv}{qB}

r=\dfrac{1.16\times 10^{-26}\ kg\times 7.86\times 10^4\ m/s}{1.6\times 10^{-19}\ C\times 0.724\ T}

r = 0.0078 meters

So, the radius of the path of the ion is 0.0078 meters. Hence, this is the required solution.

4 0
3 years ago
In the study of Physics, the "Universal Gas Law" is not considered a law at<br> all.true or false
LiRa [457]

Answer: It’s False hope this helps

Explanation:

4 0
3 years ago
Two equipotential surfaces surround a +1.70 x 10-8-C point charge. How far is the 120-V surface from the 54.0-V surface?
UNO [17]

Answer:

1.55 m

Explanation:

The potential produced by a point charge, is inversely proportional to the distance from the charge to the point where the potential is being calculated, as follows:

V =\frac{k*q}{r}

As it only depends from the distance r, we can conclude that if the potential is the same for any point to a distance r from the point charge, the equipotencial surface must be a sphere of radius r.

Replacing q = +1.7*10⁻⁸ C, and k = 9*10⁹ N*m²/C², and V, by 120 V and 54 V, we can find the distance from the charge, to the points where we are calculating the potential V, as follows:

r1 =\frac{k*q}{V1} = \frac{9e9 N*m2/C2*1.7e-8C}{120 V} = 1.28 m

r2 =\frac{k*q}{V2} = \frac{9e9 N*m2/C2*1.7e-8C}{54V} = 2.83 m

The distance between both points, is just the difference between the radius of both spheres, as follows:

r₂ - r₁ = 1.55 m

5 0
3 years ago
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