Answer:
0.8024
Explanation:
From the given question; we can say that the angular momentum of the system is conserved if the net torque is is zero.
So; 
At the closest distance ; the friction is :

According to Newton's Law:
F = ma
F = mrω²
From conservation of momentum:



However ; since the static friction is producing the centripetal force :


The coefficient of static friction between the bottoms of your feet and the surface of the turntable can now be calculated by using the formula :

= 
= ![[\frac{1200+(73(6)^2)}{((1200)+(73)(3)^2)} ]^2*[\frac{(\frac{\pi}{4})^2(3)} {9.8}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1200%2B%2873%286%29%5E2%29%7D%7B%28%281200%29%2B%2873%29%283%29%5E2%29%7D%20%5D%5E2%2A%5B%5Cfrac%7B%28%5Cfrac%7B%5Cpi%7D%7B4%7D%29%5E2%283%29%7D%20%7B9.8%7D%5D)
= 0.8024
Explanation:
It is given that,
Mass of lithium, 
It is accelerated through a potential difference, V = 224 V
Uniform magnetic field, B = 0.724 T
Applying the conservation of energy as :


q is the charge on an electron

v = 78608.58 m/s

To find the radius of the ion's path in the magnetic field. The centripetal force is balanced by the magnetic force as :



r = 0.0078 meters
So, the radius of the path of the ion is 0.0078 meters. Hence, this is the required solution.
Answer: It’s False hope this helps
Explanation:
Answer:
1.55 m
Explanation:
The potential produced by a point charge, is inversely proportional to the distance from the charge to the point where the potential is being calculated, as follows:

As it only depends from the distance r, we can conclude that if the potential is the same for any point to a distance r from the point charge, the equipotencial surface must be a sphere of radius r.
Replacing q = +1.7*10⁻⁸ C, and k = 9*10⁹ N*m²/C², and V, by 120 V and 54 V, we can find the distance from the charge, to the points where we are calculating the potential V, as follows:


The distance between both points, is just the difference between the radius of both spheres, as follows:
r₂ - r₁ = 1.55 m