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Orlov [11]
2 years ago
14

Describe the types of transportation

Physics
1 answer:
BlackZzzverrR [31]2 years ago
5 0

Answer:

1. A Spacecraft to Survive Deep Space

2. That includes food, clothing, mid-deck seats, flight tools, cameras, parachutes, safety equipment, sleep restraints and, most importantly, the astronaut spacesuits -- known as "extravehicular mobility units."

3. A new compact toilet, smaller than the one on the space station. ... suppression system or exercise equipment that helps astronauts stay in shape. New Spacecrafts

Explanation:

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Question 1 (13 marks) A charge Q is located on the top-left corner of a square. Charges of 2Q, 3Q and 4Q are located on the othe
Colt1911 [192]

Answer:

Explanation:

First of all we shall calculate electric field near charge 2Q .

electric field due to charge Q = K x Q /  (5 x 10⁻² )²

E₁  = KQ / 25 x 10⁻⁴ = KQ x 10⁴ / 25 . It is acting along positive x axis

E₁  = KQ x 10⁴  i / 25  

Similarly electric field due to charge 3Q near 2Q

=  3KQ x 10⁴  i / 25 . It is acting along y-axis

E₂ = 3KQ x 10⁴  j / 25

Similarly electric field due to charge 4Q near 2Q

=  4KQ x 10⁴  j / (25 x 2 )

= 2 KQ x 10⁴  / 25 . It is acting acting along north east direction

unit vector in north east direction = ( i + j )/ √2

So E₃ can be represented by

E₃ = 2 KQ x 10⁴  ( i + j )  / 25 x √2

Total field =  KQ x 10⁴  i / 25 + 3KQ x 10⁴  j / 25 + 2 KQ x 10⁴  ( i + j )  / ( 25 x √2 )

= KQ x 10⁴  [ i + 3 j + √2 i + √2 j ) / 25

= 400 KQ ( 2.414 i + 4.414 j )  N / C

Force on 2Q = Field x charge = 400 KQ ( 2.414 i + 4.414 j )  x 2Q  N

= 800 KQ² ( 2.414 i + 4.414 j ) N

= 800 x 9 x 10⁹ x ( 2.5 x 10⁻⁶ )² x 2.414 x ( i + 2 j ) N

= 108.63 ( i + 2 j ) N .

Magnitude of this force

= 108.63 x √5

= 243 N approx .

4 0
3 years ago
What is the mass of an object that requires 100N of force in order to accelerate 10m/s2
iragen [17]

Explanation:

Hey there!

Given;

Force (f) = 100 N

Acceleration (a) = 10m/s^2.

Mass (m)=?

We have;

Force = mass * acceleration.

So,

100 = m * 10

Or, 100 = 10m

Or, m= 100/10

Therefore, mass is 10kg.

<em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

3 0
3 years ago
These steps are followed when using the half-life of carbon-14 to determine
aniked [119]

Answer:

C. B, A,C

Explanation:

8 0
3 years ago
Read 2 more answers
A baseball player hit 60 home runs in a season. Of the 60 home runs, 19 went to right field, 18 went to right center field, 12 w
vlada-n [284]

Answer:

(a) 1/60

(b) Yes, it was unusual.

Explanation:

Number that went to the right field = 19

Number that went to the right center field = 18

Number that went to the center field = 12

Number that went to the left center field = 10

Number that went to the left field = 1

Total number of home runs = 60

(a) The probability that a randomly selected home run was hit to left ​field is

P(left field) = 1/60

(b) It was unusual because whenever a player hit a home run, it most times went to the right field,which is why the right field had the highest probability, 19/60.

On the other hand, it went to the left field the least number of times, which is why the left field had the least probability, 1/60.

So, it was unusual.

5 0
3 years ago
Given that the average glomerular capillary pressure is about 55 mmHg, plasma oncotic pressure is about 28 mmHg, and hydrostatic
Gelneren [198K]

Answer:

6.856ml/min/mmHg

Explanation:

We define the coefficient of filteration as Kf, which is a measure between the product of hydraulic conductivity and the surface area of the glomeruar capillatries. We can write it as,

Kf= \frac{GFR}{ \Omega}

Where \Omega is the Net filteration pressure,

Here we know as well that the Net filteration pressure is

\Omega = \alpha-\beta-\rho+\epsilon

Where

\alpha = The hydrostatic pressure of capillaries

\beta = The oncotic pressure in capillaries

\rho =The hydrostatic pressure in bowman capsue

\epsilon =The oncotic pressure of ultrafilterate.

\Omega=55-28-20+0

\Omega=7

Kf=\frac{120}{7}

Kf=17.14 ml/min/mmHg of filteration pressure

Each kidney weighs 125 gm so both weigh 250gms.

Expressing it for per 100 gm of kidney:

Kf_{100}= (17.14 /250)*100\\Kf_{100}=6.856ml/min/mmHg

4 0
3 years ago
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