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denis-greek [22]
3 years ago
5

The mass of the basketball shown below is 4 times the mass of the baseball.

Physics
1 answer:
igomit [66]3 years ago
8 0

Answer:

<h3>40.0 Joules. None of the answers is correct</h3>

Explanation:

Kinetic energy of an object is expressed as;

KE = 1/2mv² where;

m is the mass of the object

V is the velocity of the object.

Let Ma be the mass of the basketball and Mb be the mass of baseball.

If the mass of the basketball shown below is 4 times the mass of the baseball, then Ma = 4Mb

KE of the basket ball = 1/2MaVa²

Va² = 2(KE)a/Ma ...... 1

KE of the baseball = 1/2MbVb²

Vb² = 2(KE)b/Mb .......... 2

Since their velocities are the same, hence Va²= Vb²

2(KE)a/Ma = 2(KE)b/Mb

Substituting Ma = 4Mb into the resulting expression.

2(KE)a/4Mb = 2(KE)b/Mb

2(KE)a/4 = 2(KE)b

Given Kinetic energy of baseball (KE)b = 10.0J, the expression becomes;

2(KE)a/4 = 2(10)

2(KE)a = 4*20

2(KE)a = 80

(KE)a = 80/2

(KE)a = 40.0J

Hence the kinetic energy of the basketball is 40.0Joules

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Explanation:

(a)  Expression for change in temperature is as follows.

        |\Delta T| = |x - y|K

                         = 15.1 K

                    = |(x - 273.15) - (y - 273.15)|^{o}C

                    = |x - y|^{o}C

                    = 15.1^{o}C

Therefore, the magnitude of its temperature change in degrees Celsius is 15.1^{o}C.

(b)  Change in temperature from Celsius to Fahrenheit is as follows.

           F = 1.8C + 32

          C = \frac{F - 32}{1.8}

Since,   K = C + 273

or,    \Delta K = \Delta C = \frac{\Delta F}{1.8}

         \Delta F = 1.8 \Delta K

                      = 1.8 (15.1)

                      = 27.18^{o}F

or,                  = 27.2^{o}F

Thus, we can conclude that the magnitude of the temperature change (change in T = 15.1 K) in degrees Fahrenheit is 27.2^{o}F.

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Explanation:

First of all, we calculate the work done to accelerate the car; according to the work-energy theorem, the work done is equal to the change in kinetic energy of the car:

W=K_f -K_i= \frac{1}{2}mv^2-\frac{1}{2}mu^2

where :

K_f = \frac{1}{2}mv^2 is the final kinetic energy of the car, with

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v = 60 m/s is the final speed of the car

K_i = \frac{1}{2}mu^2 is the initial kinetic energy of the car, with

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Soolving:

W=\frac{1}{2}(2000)(60)^2 - \frac{1}{2}(2000)(30)^2=2.7\cdot 10^6 J

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Learn more about power:

brainly.com/question/7956557

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