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inna [77]
3 years ago
7

A certain chemical reaction releases of heat for each gram of reactant consumed. How can you calculate the heat produced by the

consumption of of reactant? Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols.

Chemistry
1 answer:
omeli [17]3 years ago
5 0

Complete Question

The complete question is shown in the first uploaded image

Answer:

So the math expression is  

             heat  =  \frac{ 35. 7  KJ *  1900 \ gram }{ 1 \ gram }

Explanation:

From the question we are told that

  The heat released for 1 gram of reactant consumed is  H  =  37.5 \ KJ/g

   The mass of reactant considered is  m =  1.9 \ kg  =  1900 \  g

So  if

             37.5 \ KJ is produced for  1 gram

Then

              x kJ is produced for  1900 g  

=>   x  =  \frac{ 35. 7  KJ *  1900 \ gram }{ 1 \ gram }

So the heat released is  

       heat  =  \frac{ 35. 7  KJ *  1900 \ gram }{ 1 \ gram }

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CuBr₂(aq) + Pb(CH₃COO)₂(aq) → Cu(CH₃COO)₂(aq) + PbBr₂ (s)↓

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We identify the reactants:

CuBr₂ and Pb(CH₃COO)₂

The products will be: Cu(CH₃COO)₂ and PbBr₂

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Salts from acetate are soluble.

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CuBr₂(aq) + Pb(CH₃COO)₂(aq) → Cu(CH₃COO)₂(aq) + PbBr₂ (s)↓

8 0
3 years ago
If you start with 1.000 gram sample of the isotope how much time would pass before you have just 0.100 grams of the isotope left
Vadim26 [7]

Answer:

So, you're dealing with a sample of cobalt-60. You know that cobalt-60 has a nuclear half-life of

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A radioactive isotope's half-life tells you how much time is needed for an initial sample to be halved.

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now i know the answer

6 0
3 years ago
Three common gaseous compounds of nitrogen and oxygen of different elementary composition are known: (A) laughing gas containing
Ede4ka [16]

Answer:

Please find how these data prove the law of multiple proportions below

Explanation:

The law of multiple proportions was proposed by an English chemist called John Dalton. The law states that when two elements combine and to form more than one compound. The weights/masses of the second element in the two compounds, which combines with a fixed ratio of the first element, is in a simple whole number ratio.

In this question, Nitrogen is said to combine with oxygen to give three different compounds as follows:

A) laughing gas containing 63.65% nitrogen i.e. 0.6365g

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B) colorless gas containing 46.68% nitrogen i.e. 0.4668g

This means that the mass of oxygen will be 0.5332g

C) brown toxic gas containing 30.45% nitrogen i.e. 0.3045g

This means that the mass of oxygen will be 0.6955g

The ratios of oxygen in the three compounds is therefore:

0.3635: 0.5332: 0.6955

Divide this ratio by the smallest number (0.3635)

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Multiply this ratio by 2, we have:

2: 2.9 : 3.8

Hence, the simple whole number ratio is 2:3:4.

This proves the law of multiple proportions that oxygen is in simple whole number ratio in the three different compounds.

4 0
3 years ago
Can someone help with this please?
PtichkaEL [24]
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Use the following periodic table to help you. Which of the following would be classified as a metalloid?
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Silicon is a metalloid
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