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3 years ago

The work function of a silver surface is 4.73 eV. What would happen if the silver is hit with a photon with 2.5 eV of energy?

Chemistry

2 answers:

DerKrebs [107]3 years ago

6 0

Answer:Nothing, the photon just bounces off the surface.

Explanation:

According to Albert Einstein, a photoelectron can only be emitted from a metal surface when the energy of the incident photon is greater than the work function of the metal.

In the scenario described in the question, the work function of the metal is greater than the energy of the photon. Hence, the photon just bounces off the metal surface without emitting any electron.

STatiana [176]3 years ago

5 0

Answer:

The correct option is;

C) Nothing, the photon just bounces off the surface

Explanation:

The given parameters are;

The work function of the silver surface = 4.73 eV

The amount of energy of the photon = 2.5 eV

The kinetic energy, KE $_e$ of an electron when ejected from a metal surface is given as follows;

KE $_e$ = h·f - B·E

Where;

hf = The energy of the photon

B·E = The work function of the metal

Whereby the energy of the photon impacting on the surface of the silver is equal to or larger than the work function of the silver surface, then the energy of the photon can be reach the electrons of the silver so as to be enable the electron to be ejected through the metal surface

However, given that the energy of the photon, 2.5 eV, is less than the work function of the silver surface, 4.73 eV, the kinetic energy of an ejected electron, KE $_e$ , is less 0, therefore, no electron will be ejected form the surface of the silver and the photon just bounces off the surface.

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A high speed train travels 176 miles in 7 hours. What is the speed of the train

umka21 [38]

Answer:

25 mph

Explanation:

So we have to find the unit rate, or you could use the DTS triangle, but both say you have to divide, so our equation is:

176 ÷ 7 = 25.14

But I'm going to round that

So the train is traveling at 25 mph

hope this helps:/

4 0

3 years ago

8.0 mol AgNO3 reacts with 5.0 mol Zn in

Yakvenalex [24]

Taking into account the reaction stoichiometry, 8 moles of Ag can be produced from 8 moles of AgNO₃ and 5 moles of Zn.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 AgNO₃ + Zn → 2 Ag + Zn(NO₃)₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

AgNO₃: 2 moles
Zn: 1 mole
Ag: 2 moles
Zn(NO₃)₂: 1 mole

<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of Zn reacts with 2 moles of AgNO₃, 5 moles of Zn reacts with how many moles of AgNO₃?

$amount of moles of AgNO_{3}= \frac{5 moles of Znx2 moles of AgNO_{3}}{1 mole of Zn}$

<u><em>amount of moles of AgNO₃= 10 moles </em></u>

But 10 moles of AgNO₃ are not available, 8 moles are available. Since you have less moles than you need to react with 5 moles of Zn, AgNO₃ will be the limiting reagent.

<h3>Moles of Ag formed</h3>

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 2 moles of AgNO₃ form 2 moles of Ag, 8 moles of AgNO₃ form how many moles of Ag?

$amount of moles of Ag=\frac{8 moles of AgNO_{3}x2 moles of Ag }{2 moles of AgNO_{3}}$