The work function of a silver surface is 4.73 eV. What would happen if the silver is hit with a photon with 2.5 eV of energy?
2 answers:
Answer:
The correct option is;
C) Nothing, the photon just bounces off the surface
Explanation:
The given parameters are;
The work function of the silver surface = 4.73 eV
The amount of energy of the photon = 2.5 eV
The kinetic energy, KE of an electron when ejected from a metal surface is given as follows;
KE = h·f - B·E
Where;
hf = The energy of the photon
B·E = The work function of the metal
Whereby the energy of the photon impacting on the surface of the silver is equal to or larger than the work function of the silver surface, then the energy of the photon can be reach the electrons of the silver so as to be enable the electron to be ejected through the metal surface
However, given that the energy of the photon, 2.5 eV, is less than the work function of the silver surface, 4.73 eV, the kinetic energy of an ejected electron, KE, is less 0, therefore, no electron will be ejected form the surface of the silver and the photon just bounces off the surface.
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Answer :
(a) The name for is titanium(IV) oxide.
(b) The name for is barium chloride.
(c) The name for is copper(III) chloride.
(d) The name for is potassium iodide.
(e) The name for is strontium chloride.
(f) The name for is copper(II) bromide.
Explanation :
Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.
Ionic compound are usually formed when a metal reacts with a non-metal.
The nomenclature of ionic compounds is given by:
1. Positive ion is written first.
2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.
3. In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.
(a)
is an ionic compound because titanium element is a metal and oxygen element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on tin is (+4) and the the charge on oxygen is (-2). Thus, the name for is titanium(IV) oxide.
(b)
is an ionic compound because barium element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on barium is (+2) and the the charge on chlorine is (-1). Thus, the name for is barium chloride.
(c)
is an ionic compound because copper element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on copper is (+3) and the the charge on chlorine is (-1). Thus, the name for is copper(III) chloride.
(d)
is an ionic compound because potassium element is a metal and iodine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on potassium is (+1) and the the charge on iodine is (-1). Thus, the name for is potassium iodide.
(e)
is an ionic compound because strontium element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on strontium is (+2) and the the charge on chlorine is (-1). Thus, the name for is strontium chloride.
(f)
is an ionic compound because copper element is a metal and bromine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on copper is (+2) and the the charge on bromine is (-1). Thus, the name for is copper(II) bromide.