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-Dominant- [34]
3 years ago
12

Semester Exams,Which Statement Best compares the two passages. Screenshot below,Giving Brainliest....

Chemistry
2 answers:
Ymorist [56]3 years ago
8 0
Answer D .. the first passage makes me question this answer but the second one is about a women taking her brothers place because she feels as though it needs to be done
Leona [35]3 years ago
5 0

Answer:

Answer D

Explanation:

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What part of an atom has no relative mass
Debora [2.8K]

Answer: Electrons

Explanation:

Most of an atoms' mass comes from the protons and neutrons that make up its nucleus. Electrons have the least mass of an atom's particles.

4 0
3 years ago
Read 2 more answers
You need a 70% alcohol solution. On hand, you have a 135 mL of a 20% alcohol mixture. You also have 85% alcohol mixture. How muc
frutty [35]

To obtain the desired solution:

450 mL of 85% alcohol solution is needed to obtain the desired solution.  

Calculation:

Let x be the amount of the 85% alcohol required

The volume of the resulting 70% alcohol solution will then be = x + 135 ml

135 mL of the 20% alcohol solution contains the amount of "pure" alcohol is =  0.20×135 mL.

The 85% alcohol solution contains x mL of "pure" alcohol = 0.85× x mL.

The total amount of the "pure" alcohol is the sum

=  0.20×135 + 0.85× x mL.

It should be equal to the amount of the "pure" alcohol in the mixture, which is = 0.70× (x+135) ml.

So, your "pure alcohol" equation is,  

=  0.85× x + 0.20×135 = 0.70× (x+135)

Simplify and solve it for x:

0.85x + 0.20×135 = 0.70x + 0.70×135,

0.85x - 0.70x = 0.70×135 - 0.20×135,

0.15x = 67.5

x = 67.5/0.15

= 450mL.

Learn more about the alcohol solution here,

brainly.com/question/12246176

#SPJ4

 

7 0
2 years ago
For the gas phase decomposition of 1-bromopropane, CH3CH2CH2BrCH3CH=CH2 + HBr the rate constant at 622 K is 6.43×10-4 /s and the
Radda [10]

Answer is: activation energy of this reaction is 212,01975 kJ/mol.<span>
Arrhenius equation: ln(k</span>₁/k₂) = Ea/R (1/T₂ - 1/T₁).<span>
k</span>₁ = 0,000643 1/s.<span>
k</span>₂ = 0,00828 1/s.

T₁ = 622 K.

T₂ = 666 K.

R = 8,3145 J/Kmol.

<span> 1/T</span>₁ = 1/622 K = 0,0016 1/K.<span>
1/T</span>₂ = 1/666 K = 0,0015 1/K.<span>
ln(0,000643/0,00828) = Ea/8,3145 J/Kmol · (-0,0001 1/K).
-2,55 = Ea/8,3145 J/Kmol </span>· (-0,0001 1/K).<span>
Ea = 212019,75 J/mol = 212,01975 kJ/mol.</span>

6 0
3 years ago
Add the polynomials (7x^3-2x^2-12)+(3x^3-8x^2+10x)
laiz [17]

Answer:

10 x ^3 − 10 x ^2 + 10 x − 12

Explanation:

4 0
3 years ago
In which grouping of the periodic table do the elements have simliar properties
STatiana [176]
I would have to say [c]

but it could also be [b]

3 0
3 years ago
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