Answer:
749 grams CO₂
Explanation:
To find the amount of carbon dioxide produced, you need to (1) convert grams C₃H₈ to moles C₃H₈ (via molar mass from periodic table), then (2) convert moles C₃H₈ to moles CO₂ (via mole-to-mole ratio via reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass from periodic table). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The desired unit should be in the numerator. The final answer should have 3 significant figures because the given value (250. grams) has 3 sig figs.
Molar Mass (C₃H₈): 3(12.01 g/mol) + 8(1.008 g/mol)
Molar Mass (C₃H₈): 44.094 g/mol
1 C₃H₈ + 5 O₂ ---> 3 CO₂ + 4 H₂O
Molar Mass (CO₂): 12.01 g/mol + 2(16.00 g/mol)
Molar Mass (CO₂): 44.01 g/mol
250. g C₃H₈ 1 mole C₃H₈ 3 moles CO₂ 44.01 g
------------------ x ---------------------- x ---------------------- x -------------------- =
44.094 g 1 mole C₃H₈ 1 mole CO₂
= 749 grams CO₂
Answer:
B) A piece of metal in water and produces spark and gas
Answer:
Kp = 9.3x10⁴
Explanation:
The reaction is this:
4PBr₃ (g) ⇄ P₄ (g) + 6Br₂ (g)
We define Kp from the partial pressures in equilibrium
PBr₃ → 97.4 atm
P₄ → 99.2 atm
Br₂ → 97.2 atm
Kp = (Partial pressure Br₂)⁶ . (Partial pressure P₄) / (Partial pressure PBr₃)⁴
Kp = 97.2⁶ . 99.2 / 97.4⁴
Kp = 929551.4533
929551.4533 → 9.3x10⁴
