PLEASE HELP IMMEDIATE WORTH 10 POINTS

The process of photosynthesis converts _____ energy into _____ energy.

muminat

I believe the answer is A) light; chemical

7 0

3 years ago

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If 15 ml of water is added to a solution of hydrochloric acid with a pH of 2, how will the solution change?

Katarina [22]

Answer:

pH of the solution will slightly increase as it becomes less acidic for which it turns out to be more diluted.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the pH change of the solution by firstly calculating the HCl concentration, as equal to that of the hydrogen ions whose pH is 2 as this is a strong acid:

$[HCl]=[H^+]=10^{-pH}=10^{-2}=0.01M\\$

Now, since water is added to the solution, but we do not have the initial volume of this solution, we can ensure that its pH will increase, become less acidic, because the concentration of the acid, and consequently that of the hydrogen ions, is diminished as the volume is increased.

Best regards!

5 0

3 years ago

Which of the following forms a covalent bond with nitrogen?

wariber [46]

B calcium I believe is the answer

3 0

3 years ago

Calculate the molarity of sodium ion in a solution made

Arada [10]

Answer:

0.1035 M

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Sodium chloride will furnish Sodium ions as:

$NaCl\rightarrow Na^{+}+Cl^-$

Given :

For Sodium chloride :

Molarity = 0.288 M

Volume = 3.58 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 3.58×10⁻³ L

Thus, moles of Sodium furnished by Sodium chloride is same the moles of Sodium chloride as shown below:

$Moles =0.288 \times {3.58\times 10^{-3}}\ moles$

Moles of sodium ions by sodium chloride = 0.00103104 moles

Sodium sulfate will furnish Sodium ions as:

$Na_2SO_4\rightarrow 2Na^{+}+SO_4^{2-}$

Given :

For Sodium sulfate :

Molarity = 0.001 M

Volume = 6.51 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 6.51 ×10⁻³ L

Thus, moles of Sodium furnished by Sodium sulfate is twice the moles of Sodium sulfate as shown below:

$Moles =2\times 0.001 \times {6.51\times 10^{-3}}\ moles$

Moles of sodium ions by Sodium sulfate = 0.00001302 moles

Total moles = 0.00103104 moles + 0.00001302 moles = 0.00104406 moles

Total volume = 3.58 ×10⁻³ L + 6.51 ×10⁻³ L = 10.09 ×10⁻³ L

Concentration of sodium ions is:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity_{Na^+}=\frac{0.00104406}{10.09\times 10^{-3}}$

<u> The final concentration of sodium anion = 0.1035 M</u>

4 0

4 years ago

An indicator with a lower pka will have a color change interval that is _____ on the ph scale.

Ulleksa [173]

An indicator with a lower pka will have a color change interval that is base on the ph scale.

Since indicators are weak acids or bases, they change form as the pH fluctuates. When the indicator's pKa and pH are numerically equal, the indicator will be composed of 50% acid and 50% basic forms. One unit higher in pH results in 10% acid form and 90% basic form. As a result, there occurs a progressive switch from almost exclusively acid to almost exclusively base form.

As the ratio of acid to base changes, the colour of the indicator also changes because indicators come in both acid and basic forms. For our eyes to see a colour as pure red or pure yellow, for example, a ratio of roughly 10:1 is typically required.

The precise ratio will depend on the compound's absorbance and how sensitive our eyes are to a particular colour. However, we will typically observe a change over a pH range of about 2 from pKa -1 (90% acid) to pKa +1 (90% basic).

Learn more about indicator here;
brainly.com/question/8876896

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5 0

1 year ago