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defon
3 years ago
8

Which of the following is NOT a benefit of using renewable energy sources?

Chemistry
2 answers:
nasty-shy [4]3 years ago
6 0
The answer would be considered D.
Afina-wow [57]3 years ago
3 0

Answer:

D, They produce fossil fuels

Explanation:

you can't just pull them out of nowhere

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[11]. Of these four liquids, which is the most viscous?
-Dominant- [34]
The most viscous among the choices is D. Honey at room temperature.

Viscosities of liquids typically vary with temperature. The higher the temperature, the lower the viscosity. Among the choices, only motor oil and honey appear to be the most viscous. The clue that helps determined the answer are the words "hot" and "room temperature". Hot motor oil is less viscous, while honey at room temperature is more viscous. Even comparing their viscosities at room temperature, honey already has a higher viscosity than motor oil.
6 0
3 years ago
How can melting point and boiling point identify a substance
Nikolay [14]

Answer:

to determine of it is a solid liquid or gas.

Explanation:

The melting point is the temperature at which a substance converts from a solid state to a liquid state.

8 0
4 years ago
A compound whose water solution conducts electricity and turns phenolphthalein pink is
Ede4ka [16]

Answer:

The compound is an <em>alkali</em>

Explanation:

Although acids and bases in solution can conduct electricity due to the presence of free ions available to carry charges, bases or alkalis turn phenolphthalein indicator pink; as opposed to acids which give colourless test on the indicator.

The anayte compound is therefore a concentrated alakli solution.

4 0
3 years ago
Radiaciones de ionización directa y de ionización indirecta.
Aleksandr [31]

Answer:

ola what do u need to do?

5 0
3 years ago
given the following equation: 8 H2 + S8 −−&gt; 8H2S what is the molar relationship between H2 and H2S
PSYCHO15rus [73]
-(1/8)Δ[H2S]/Δt = -(1/4)Δ[O2]/Δt
(1/8)Δ[H2S]/Δt = (1/4)Δ[O2]/Δt
(4)*((1/8)Δ[H2S]/Δt) = (4*)((1/4)Δ[O2]/Δt)
(1/2)Δ[H2S]/Δt = Δ[O2]/Δt
(1/2))*( -0.057 M/s) = Δ[O2]/Δt
Δ[O2]/Δt = -0.0285 M/s
4 0
3 years ago
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