Answer:
- <u><em>294.307 g/mol</em></u>
Explanation:
The first question for this statment is:
- <em>Calculate the gram-formula-mass of aspartame. </em>
<em />
<h2>Solution</h2>
The chemical formula is:
The <em>gram-formula-mass </em>is calculated adding the masses for all the atoms in the molecular formula:
Atom Number of atoms Atomic mass Total mass
g/mol g/mol
C 14 12.011 14 × 12.011 = 164.154
H 18 1.008 18 × 1.008 = 18.144
N 2 14.007 2 × 14.007 = 28.014
O 5 15.999 5 × 15.999 = 79.995
===================
Total 294.307 g/mol
Answer: 294.307 g/mol
STP condition mean we have P=1 atm. T=273K. R=ideal gas constant, but make sure you use the one that has the same units of pressure, temperature that you are using. In this case R=0.0821 L*atm K^-1mol^1. You are provided with n=2.1 moles.
V=nRTP
Input your values and solve.
Answer:
8.3ml
Explanation:
to get volume u have to divide 25g over the density, i rounded to the nearest tenth, if you don't want to then write out the full number with all the decimals
The state of matter is liquid.
Answer: 66.2 g
Explanation:
1) The ratio of Al in the molecule is 1 mol to 1 mol .
2) The mass of 1 mol of molecules of Al (CH2H3O2)3 is the molar mass of the compound.
3) You calculate the molar mass of the compound using the atomic masses of each atom, in this way:
Al: 27 g/mol
C: 2 * 3 * 12 g/mol = 72 g/mol
H: 3 * 3 * 1 g/mol = 9 g/mol
O: 2 * 3 * 16 g/mol = 96 g/mol
Molar mass = 27 g/mol + 72 g/mol + 9 g/mol + 96 g/mol = 204 g/mol
4) Set a proportion:
27 g/mol x
-------------------- = ----------
204 g/mol 500 g
5) Solve for x:
x = 500 g * 27 g/mol / 204 g/mol = 66.2 g
