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choli [55]
3 years ago
14

Indicate whether the following statements are true or false for a reversible process: (A) Q=0. (B) Work may be calculated using

the equation of state. (C) The entropy change of the system is zero. (D) The total entropy change of the system and the surroundings is zero.
Engineering
1 answer:
mafiozo [28]3 years ago
4 0

Answer:

A).False

B).False

C).False

D).True

Explanation:

As we know that ,when system and surrounding return in initial position without leaving any effect on the surrounding then it is called reversible process.

Option A is false because this is not a adiabatic process.

Option B we know that work is path function and it depends on the path even process is reversible or irreversible.That is why option B is false.

Option C is false because we can not say that entropy change of system is zero.The entropy of system can be increase or decrease we can not say anything.

Option D is true because the entropy of universe is always zero for a reversible process.Universe is the summation of surrounding and system.

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Using data in Appendix A ,calculate the number of atoms in 1 tonne of iron
maksim [4K]
<h2>Answer:</h2>

1.0783*10^{28}(atoms).

<h2>Explanation:</h2>

<em>Since I don't have access to "Appendix A", I'll solve the problem using data from the periodic table.</em>

<em />

<h3>1. Determine the molar mass of iron.</h3>

<em>According to the periodic table, the molar mass of iron is:</em>

55.845g/mole.

<h3>2. Convert 1 tonne to grams.</h3>

1(tonne)*1000=1000kg\\1000kg*1000=1000000g=10^6g

<h3>3. Apply rule of 3.</h3>

55.845g ----------- 1 mole

10^6g ----------- x

x=\frac{10^6*1}{55.845}=17906.7061(moles)

<h3>4. Determine the amount of atoms.</h3>

<em>Considering that there are, approximately, </em>6.022*10^{23} atoms in a mole of any element, apply another rule of 3.

1 mole --------------------- 6.022*10^{23}(atoms)

17906.7061(moles) --------------------- x

x=\frac{17906.7061*6.022*10^{23}}{1}=1.0783*10^{28}.

4 0
2 years ago
You have a solid square copper ground support, 2 inch per side X 6 inches tall, and it is loaded axially (long axis)with 1600 po
Aleks04 [339]

Answer:

The solution is given in the attachments.

5 0
3 years ago
What information on a piping arrangement drawing gives the vertical placement of an item?
Yakvenalex [24]

Answer:

c) Elevations

Explanation:

Elevations in pipe systems design provide the views necessary in presenting a pipe isometrics indicating the pipe length, wideness of a line and the height of a pipe.The drafts person obtains the true north coordinates in the desired points where the pipeline is to pass and determines the required vertical grade where all vertical measurements will be referred.

4 0
4 years ago
Microchips found inside most electronic devices today are examples of what material A. Polymers B. Alloys C. Composites D. None
dedylja [7]

Answer: A

Explanation:

Microchips are made out of silicone witch is a polymer.

6 0
3 years ago
Read 2 more answers
A car is moving at 68 miles per hour. The kinetic energy of that car is 5 × 10 5 J.How much energy does the same car have when i
Blababa [14]

Answer:

The car has an energy of 1.017 × 10⁵ J when it moves at 97 miles per hour

Explanation:

Given the data in the question;

Initial velocity v₁ = 68 miles per hour = 30.398 meter per seconds

let mass of the car be m

kinetic energy of that car is 5 × 10⁵ J

so

E₁ = \frac{1}{2}mv²

we substitute

5 × 10⁵  = \frac{1}{2} × m × ( 30.398 )²

5 × 10⁵  = \frac{1}{2} × m × ( 30.398 )²

5 × 10⁵ = m × 462.019

m =  5 × 10⁵ / 462.019

m = 1082.2065 kg

Now, Also given that; v₂ = 97 miles per hour = 43.362 meter per seconds

E₂ = \frac{1}{2}mv₂²

we substitute

E₂ = \frac{1}{2} × 1082.2065 × ( 43.362 )²

E₂ = \frac{1}{2} × 1082.2065 × 1880.263

E₂ = 1.017 × 10⁵ J

Therefore, The car has an energy of 1.017 × 10⁵ J when it moves at 97 miles per hour

6 0
3 years ago
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