Question

How much energy is required to remove a proton from 157N? The masses of the atoms 157N, 146C and 11H are 15.000109 u, 14.003242 u and 1.007825 u, respectively. How much energy is required to remove a neutron? The mass of a neutron is 1.008665 u.

Answer 1

Answer:

10.207377 MeV

10.833345 MeV

Explanation:

c = Speed of light = $3\times 10^8\ m/s$

The reaction to remove a proton is as follows

$^{15}_7N=^{14}_6C+^{1}_1H$

From the mass energy equivalence

$E=(14.003242+1.007825-15.000109)u\times (c)^2\\\Rightarrow E=0.010958uc^2\\\Rightarrow E=0.010958\times 931.5\\\Rightarrow E=10.207377\ MeV$

The energy is required to remove a proton is 10.207377 MeV

The reaction to remove a proton is as follows

$^{15}_7N=^{14}_7N+n$

From the mass energy equivalence

$E=(14.003074+1.008665-15.000109)u\times (c)^2\\\Rightarrow E=0.01136uc^2\\\Rightarrow E=0.01163\times 931.5\\\Rightarrow E=10.833345\ MeV$

Mass of $^{14}_7N=14.003074u$

The energy is required to remove a neutron is 10.833345 MeV