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disa [49]
3 years ago
14

What is the density of iron if 5.0 cm3 has a mass of 39.5g

Physics
1 answer:
weqwewe [10]3 years ago
7 0

Answer :\rho = 7.9\ g/cm^3

Explanation :

It is given that

Mass of iron, m = 39.5 g

Volume of iron, V = 5\ cm^3

So, density is :

density, \rho =\dfrac{mass}{volume}

\rho =\dfrac{39.5g}{5cm^3}

\rho = 7.9\ g/cm^3

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For a particular type of motion, the velocity is zero but the speed is a nonzero quantity. Which statement can you make about th
masha68 [24]

Answer:

because speed is the modulus of velocity which is a vector

the velocity to be zero it must be a round trip

Explanation:

This is because speed is the modulus of velocity which is a vector.

For the velocity to be zero it must be a round trip, therefore the resulting vector zero

On the other hand, the speed of the module is the same in both directions

8 0
3 years ago
How is temperature related to the physical change of a<br>substance​
blagie [28]

Answer:

~~Now, you have left your question very open ended and didn't ask for any particular kind of answer so I'll do my best to get what you're looking for.~~

A physical change in a substance doesn't change what the substance is. It can possibly melt or freeze an object. I mean heat makes things expand while cooling makes them retract.... In chemical change where there is a chemical reaction, a new substance is formed and energy is either given off or absorbed.

4 0
3 years ago
Read 2 more answers
A tennis ball is shot vertically upward in an evacuated chamber inside a tower with an initial speed of 20.0 m/s at time t=0s. W
dalvyx [7]

Answer:

at the highest point of the path the acceleration of ball is same as acceleration due to gravity

Explanation:

At the highest point of the path of the ball the speed of the ball becomes zero as the acceleration due to gravity will decelerate the motion of ball due to which the speed of ball will keep on decreasing and finally it comes to rest

So here we will say that at the highest point of the path the speed of the ball comes to zero

now by the force diagram we can say that net force on the ball due to gravity is given by

F_g = mg

now the acceleration of ball is given as

a = \frac{F_g}{m}

a = \frac{mg}{m} = g

so at the highest point of the path the acceleration of ball is same as acceleration due to gravity

5 0
3 years ago
A ball is thrown vertically downward from the top of a 30.6-m-tall building. The ball passes the top of a window that is 10.7 m
Gekata [30.6K]

Answer:

v = 19.6 m/s

Explanation:

Height of building = 30.6 m.

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Lets take when passes through the window ,velocity is v.

Here acceleration is constant so we can apply motion equation .

We know that

v= u + a t

So by putting the values

v = 0 +9.8 x 2

v = 19.6 m/s

So the velocity of ball is 19.6 m/s when passes through the window after 2 s.

7 0
3 years ago
A shotputter throws the shot with an initial speed of 15.6 m/s at a 30.0 degree angle to the horizontal. Calculate the horizonta
vfiekz [6]
To calculate the horizontal distance traveled by the shot if it leaves the athlete's hand at a height of 2.20 above the ground we can get the root of the quad equation for time are t=-0.24 or t =1.84 taking the t = 1.84, so the equation will be:
x = 15.6cos(30) * 1.86, x = 24.79m
8 0
3 years ago
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