Question

In t-ball, young players use a bat to hit a stationary ball off a stand. The 140 g ball has about the same mass as a baseball, but it is larger and softer. In one hit, the ball leaves the bat at 12 m/s after being in contact with the bat for 2.0 ms . Assume constant acceleration during the hit.

Answer 1

Question is missing. Found on google:

"Part A What is the acceleration of the ball? Express your answer to two significant figures and include the appropriate units.

Part B

What is the net force on the ball during the hit?  

Express your answer to two significant figures and include the appropriate units."

Solution:

A) $6000 m/s^2$

The acceleration of the ball is given by

$a=\frac{v-u}{t}$

where

v = 12 m/s is the final velocity

u = 0 is the initial velocity (the ball is stationary)

t = 2.0 ms = 0.002 s is the time of contact

Substituting,

$a=\frac{12-0}{0.002}=6.0 \cdot 10^3 m/s^2$

B) $8.4\cdot 10^2 N$

The force on the ball can be found by using Newton's second law:

$F=ma$

where

m = 140 g = 0.14 kg is the mass of the ball

$a=6.0\cdot 10^3 m/s^2$ is the acceleration

Substituting,

$F=(0.14)(6.0\cdot 10^3)=8.4\cdot 10^2 N$