A charged ball is moving horizontally and perpendicular to a magnetic field of 0.8 Tesla. The ball has a mass of 0.007 kg and ha
2 answers:
Answer:
17.15 m/s
Explanation:
Parameters given:
Magnetic field, B = 0.8 T
Mass of ball, m = 0.007 kg
Charge of ball, q = 0.005 C
The magnetic force acting on the charged ball due to the magnetic field is given as:
F = qvBsinθ
where v = velocity of the ball and θ = angle between the horizontal and the magnetic field = 90°
The force of the ball will be in the opposite direction but of equal magnitude:
= -qvBsin(90) = -qvB
To cancel out the effect of gravity, the magnetic force must be equal to the gravitational force acting on the ball:
F = mg
Therefore:
mg = -qvB
Solving for velocity, v, we have:
v = 17.15 m/s
The ball must be moving at a velocity of 17.15 m/s.
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Answer:
Yes
Explanation:
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Answer:
Current, I = 1000 A
Explanation:
It is given that,
Length of the copper wire, l = 7300 m
Resistance of copper line, R = 10 ohms
Magnetic field, B = 0.1 T
Resistivity,
We need to find the current flowing the copper wire. Firstly, we need to find the radius of he power line using physical dimensions as :
r = 0.00199 m
or
The magnetic field on a current carrying wire is given by :
I = 1000 A
So, the current of 1000 A is flowing through the copper wire. Hence, this is the required solution.