A charged ball is moving horizontally and perpendicular to a magnetic field of 0.8 Tesla. The ball has a mass of 0.007 kg and ha
2 answers:
Answer:
17.15 m/s
Explanation:
Parameters given:
Magnetic field, B = 0.8 T
Mass of ball, m = 0.007 kg
Charge of ball, q = 0.005 C
The magnetic force acting on the charged ball due to the magnetic field is given as:
F = qvBsinθ
where v = velocity of the ball and θ = angle between the horizontal and the magnetic field = 90°
The force of the ball will be in the opposite direction but of equal magnitude:
= -qvBsin(90) = -qvB
To cancel out the effect of gravity, the magnetic force must be equal to the gravitational force acting on the ball:
F = mg
Therefore:
mg = -qvB
Solving for velocity, v, we have:
v = 17.15 m/s
The ball must be moving at a velocity of 17.15 m/s.
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Answer:
The particle’s velocity is -16.9 m/s.
Explanation:
Given that,
Initial velocity of particle in negative x direction= 4.91 m/s
Time = 12.9 s
Final velocity of particle in positive x direction= 7.12 m/s
Before 12.4 sec,
Velocity of particle in negative x direction= 5.32 m/s
We need to calculate the acceleration
Using equation of motion
Where, v = final velocity
u = initial velocity
t = time
Put the value into the equation
We need to calculate the initial speed of the particle
Using equation of motion again
Put the value into the formula
Hence, The particle’s velocity is -16.9 m/s.