examining the structure of plant cells
Answer:
At equilibrium, the concentration of 
is going to be 0.30M
Explanation:
We first need the reaction.
With the information given we can assume that is:
+ 
⇄ 2
If there is placed 0.600 moles of NO in a 1.0-L vessel, we have a initial concentration of 0.60 M NO; and no nor present. Immediately, and are going to be produced until equilibrium is reached.
By the ICE (initial, change, equilibrium) analysis:
I: []=0 ; [ ]= 0 ; []=0.60M
C: []=+x ; [ ]= +x ; []=-2x
E: []=0+x ; [ ]= 0+x ; []=0.60-2x
Now we can use the constant information:
![K_{c}=\frac{[products]^{stoichiometric coefficient} }{[reactants]^{stoichiometric coefficient} }](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5Bproducts%5D%5E%7Bstoichiometric%20coefficient%7D%20%7D%7B%5Breactants%5D%5E%7Bstoichiometric%20coefficient%7D%20%7D)
= 
= 
= 
At equilibrium, the concentration of is going to be 0.30M
The specific gravity of the solution is 1.07, which contains 5.34g for a 5.00ml sample.
Density of a substance is
Density = Mass / Volume
= 5.34/5
= 1.07
Density of water = 1
Specific gravity = Density of substance/density of solvent
Specific gravity = 1.07 / 1
Specific gravity = 1.07
Specific gravity, often known as relative density, is the ratio of a substance's density to that of an industry standard.
If a material has a relative density that is less than 1 compared to the reference, it is less dense than the reference; if it is larger than 1, it is denser. Identical volumes of the two substances have the same mass if the relative densities are equal, or exactly 1.
To learn more about specific gravity click the given link
brainly.com/question/543765
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A. high potential energy and zero kinetic energy.
