Answer:
3m/s²
Explanation:
Given parameters:
Mass of object = 3.2kg
Force to the right = 16.3N
Force to the left = 6.7N
Unknown:
Acceleration of the object = ?
Solution:
To solve this problem, we use newtons second law of motion;
Net force = mass x acceleration
Net force on object = Force to the right - Force to the left
Net force = 16.3N - 6.7N = 9.6N
So;
9.6 = 3.2 x a
a =
= 3m/s²
Answer:
![3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-](https://tex.z-dn.net/?f=3H_2O%2B%28Bi%5E%7B5%2B%7DO_3%29%5E-%5Crightarrow%20Bi%5E%7B3%2B%7D%2B6OH%5E-)
Explanation:
Hello there!
In this case, according to the required half-reaction, we start by setting it up from bismuth (V) oxide ion to bismuth (III) ion:
![BiO_3^-\rightarrow Bi^{3+}](https://tex.z-dn.net/?f=BiO_3%5E-%5Crightarrow%20Bi%5E%7B3%2B%7D)
Thus, next realize that the oxidation state of Bi in BiO3^- is 5+ because oxygen is 2- (-2*3+x=-1;x=-1+6;x=+5), so we obtain:
![(Bi^{5+}O_3)^-\rightarrow Bi^{3+}](https://tex.z-dn.net/?f=%28Bi%5E%7B5%2B%7DO_3%29%5E-%5Crightarrow%20Bi%5E%7B3%2B%7D)
Thereafter, we realize three water molecules are needed on the right in order to balance the oxygens and consequently 6 hydrogen atoms on the left to balance hydrogen:
![6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O](https://tex.z-dn.net/?f=6H%5E%2B%2B%28Bi%5E%7B5%2B%7DO_3%29%5E-%5Crightarrow%20Bi%5E%7B3%2B%7D%2B3H_2O)
Now, since the balance is is basic media, we add six molecules of hydroxide ions in order to produce water with the hydrogen ones:
![6OH^-+6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O-3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-](https://tex.z-dn.net/?f=6OH%5E-%2B6H%5E%2B%2B%28Bi%5E%7B5%2B%7DO_3%29%5E-%5Crightarrow%20Bi%5E%7B3%2B%7D%2B3H_2O%2B6OH%5E-%5C%5C%5C%5C6H_2O%2B%28Bi%5E%7B5%2B%7DO_3%29%5E-%5Crightarrow%20Bi%5E%7B3%2B%7D%2B3H_2O%2B6OH%5E-%5C%5C%5C%5C6H_2O-3H_2O%2B%28Bi%5E%7B5%2B%7DO_3%29%5E-%5Crightarrow%20Bi%5E%7B3%2B%7D%2B6OH%5E-)
Then, we accommodate the waters to obtain:
![3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-](https://tex.z-dn.net/?f=3H_2O%2B%28Bi%5E%7B5%2B%7DO_3%29%5E-%5Crightarrow%20Bi%5E%7B3%2B%7D%2B6OH%5E-)
Best regards!
Answer:
Explanation:
turn over number = R max / [E]t = K2
From given , R max = 249 * 10 ^ -6 mol. L^-1
T [E]t = 2.23 n mol. L^-1
= 2.23 * 10^-9 mol. L^-1
Putting values in above equation,
= 111.65 * 10^3 S^-1
Turn over number is maximum no of substrate molecule that can be converted into product molecules for unit time by enzyme molecule.
The process that is physical changes is:
- mixing frozen orange juice concentrate with water
<h3>What is a physical change?</h3>
A physical change can be described as a type of change that take place in physical without chemical reaction as opposed to chemical change.
They are changes that are usually reversible it should be noted that physical change do not involve the alterations as regards the chemical make up of a particular substance and as a result of this , in physical change, there is no formation of new product.
Therefore, The process that is physical changes is mixing frozen orange juice concentrate with water
Read more about physical changes here:
brainly.com/question/13056570
#SPJ1
So the empirical formula is Mg3N2