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sleet_krkn [62]

3 years ago

9

An inductor of 299 mH with a resistance of 51 Ω is connected to a power supply with a maximum voltage of 227 V and a frequency o

f 72 Hz. Find the current in the circuit. Answer in units of A.

1 answer:

kramer3 years ago

6 0

Answer:

The answer is 1.1A

Explanation:

See the attached file

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Trumpeter A holds a B-flat note on the trumpet for a long time. Person C is running towards the trumpeter at a constant velocity

Vikki [24]

You didn't mention it, but the trumpeter herself has to be standing still.

<span>Person C, the one running towards the trumpeter, hears a pitch
that is higher than B-flat. (A)

Person B, the one running away from the trumpeter, hears a pitch
that is lower than B-flat.

Person D, the one standing still the whole time, hears the B-flat.</span>

5 0

3 years ago

Read 2 more answers

An object with velocity 141 ft/s has a kinetic energy of 1558.71 ftâˆ™lbf, on a planet whose gravity is 31.5 ft/s2. What is its

Sidana [21]

Answer:

The mass of the object is 5.045 lbm.

Explanation:

Given;

kinetic energy of the object, K.E = 1558.71 ft.lbf

velocity of the object, V = 141 ft/s

The kinetic energy of the object is calculated as;

$K.E = \frac{1}{2} mV^2\\\\mV^2 = 2K.E\\\\m = \frac{2K.E}{V^2} \\\\1 \ lbf = 32.174 \ lbm.ft/s^2\\\\m = \frac{2 \ \times \ 1558.71 \ ft.lbf \ \times \ 32.174 \ lbm.ft/s^2 }{(141 \ ft/s)2 \ \ \times \ \ \ \ 1 \ lbf\ }$

$m = \frac{(2 \ \times \ 1558.71 \ \times \ 32.174) \ lbm.ft^2/s^2 }{(141 )^2\ ft^2/s^2 }\\\\m = \frac{(2 \ \times \ 1558.71 \ \times \ 32.174) \ lbm }{(141 )^2 }\\\\m = 5.045 \ lbm$

Therefore, the mass of the object is 5.045 lbm.

6 0

2 years ago

Political scientists use political models to describe which of the following? a. political spectrum b. political shift c. politi

aniked [119]

Answer:

D

Explanation:

Political scientists use political models to describe the political climate, which is an aggregate mood or opinion of a political society at a point in time.

8 0

2 years ago

Read 2 more answers

An object moving in the xy-plane is subjected to the force f⃗ =(2xyı^ 3yȷ^)n, where x and y are in m

ryzh [129]

The work done by the applied force on the object is (2ab²i + 3b²j) J.

<h3>Magnitude of the force on the object</h3>

The magnitude of the force on the object is calculated as follows;

f = (2xyi + 3yj)

when;

x = a, and y = b

f = (2abi + 3bj)

<h3>Work done by the force</h3>

The work done the applied force is the product of force and displacement of the object.

W = fΔs

where;

Δs is displacement of the object

Δx = a - a = 0

Δy = 0 - b = -b

Δs = √(Δx² + Δy²)

Δs = √(-b)²

Δs = b

W = (2abi + 3bj) x b

W = (2ab²i + 3b²j) J

Thus, the work done by the applied force on the object is (2ab²i + 3b²j) J.

The complete question is below;

An object moving in the xy-plane is subjected to the force f = (2xyi + 3yj), where x and y are in m. The particle moves from the origin to the point with coordinates (a, b) by moving first along the x-axis to (a, 0), then parallel to the y-axis. How much work does the force do?

Learn more about work done here: brainly.com/question/8119756

6 0

1 year ago

Earth has a magnetic dipole moment of 8.0 × 1022 J/T. (a) What current would have to be produced in a single turn of wire extend

Bogdan [553]

Answer:

a

The current that would be produced is $I = 6.26 *10 ^8 A$

b

Yes this arrangement can be used to cancel out earths magnetic field at points well above the Earth's surface.This is because this current loop acts as a magnetic dipole for point above the earth surface

c

No this arrangement can not be used to cancel out earths magnetic field at points on the Earth's surface .this because on the earth surface it shifts from its behavior as a magnetic dipole

Explanation:

From the question we are told that

The magnetic moment of earth is $M = 8.0*10 ^{22} J/T$

The radius of earth generally has a value of $R = 6378 *10^3 m$

Magnetic moment is mathematically given as

$M = IA$

A is the area of the of the earth(assumption that the earth is circular ) and this evaluated as

$A = \pi R^2$

Now making $I$ the subject in the above formula

$I = \frac{M}{A}$

$= \frac{M}{\pi R^2}$

$= \frac{8.0^10^{22}}{\pi (6378 *10^{3})^2}$

$= 6.26 *10^8 A$

5 0

2 years ago