Answer:
the distance traveled by the car is 42.98 m.
Explanation:
Given;
mass of the car, m = 2500 kg
initial velocity of the car, u = 20 m/s
the braking force applied to the car, f = 5620 N
time of motion of the car, t = 2.5 s
The decelaration of the car is calculated as follows;
-F = ma
a = -F/m
a = -5620 / 2500
a = -2.248 m/s²
The distance traveled by the car is calculated as follows;
s = ut + ¹/₂at²
s = (20 x 2.5) + 0.5(-2.248)(2.5²)
s = 50 - 7.025
s = 42.98 m
Therefore, the distance traveled by the car is 42.98 m.
Answer:
Explanation:
Given data
Electric potential at point a is Ua=5.4×10⁻⁸J
q₂ moves to point b where a negative work done on it 
Required
Electric potential energy Ub
Solution
When a particle moves from a point where the potential is Ua to a point where it is Ub the change in potential energy is equal to work done where the force exerted on the charge is conservative and work done is given by:
Now substitute the given values
So
Answer:
B. The atom gains 1 electron, to make a total of 18 electrons.
Explanation:
Chlorine is the 17th element in the periodic table, so it has atomic number 17:
Z = 17
This means that a neutral atom of chlorine has 17 protons and 17 electrons.
When a chlorine atom gains 1 electron, its electric charge (initially zero) becomes -1, since the electron has negative charge of -1 (in elemntary charge units). This also means that the number of electrons in the ion is now
17 + 1 = 18
So the correct answer is
B. The atom gains 1 electron, to make a total of 18 electrons
Thinking the small glass bead as a single point charge, the electric field generated by it is given by
where
is the Coulomb's constant
is the charge of the bead
is the distance at which we calculate the field.
Using these data, we find:
Answer:
Distance is 500 m, displacement is 0
Explanation:
Distance and displacement are defined in two different ways:
- Distance is the total length of the path covered by an object in motion - so it depends on the path taken. In this problem, the distance travelled by the car corresponds to the length of one lap, which is the length of the track, so 500 m
- Displacement is the distance in a straight line between the final point and the initial point of the motion. This means that displacement does not depend on the path taken, but only on the starting and ending point of the motion. In this problem, the car completes one lap, so the final position of the car is equal to its starting position - therefore the displacement is zero, since the distance between these two points is zero.
