Answer:
0.0619 m^3
Explanation
number of moles = n = 4.39 mol
pressure = P = 2.25 atm =2.25×1.01×10^5 Pa= 2.27×10^5 Pa
Molar gas constant =R = 8.31 J/(mol K)
Temperature T= 385K
volume of gas = V =?
BY GENERAL GAS LAW WE HAVE
PV = nRT
or V = nRT/P
or V = (4.39×8.31×385)/(2.27×10^5)
V = 0.0618728
V = 0.0619 m^3
Explanation:
Using Ohm's Law and a bit of substitution, we can use voltage divided by current to solve for resistance. Doing that, we'll get 6 Ohm.
To solve this, you’d multiply 55 by 4, because he is travelling 55 miles every hour, for four hours, which means 55 miles every hour. The answer would be 220.
Answer:
-5.24 m/s
** The minus sign indicates that the velocity vector points in the opposite direction with respect to the initial direction of the 77.8 kg player **
Explanation:
Hi!
We can solve this problem considering each player as a point particle and taking into account the conservation of linear momentum.
Since the 99.8 kg player is moving towards the 77.8kg, the initial total momentum is:
m1*v1_i + m2*v2_i = (77.8kg)(8.1 m/s) - (99.8kg)(6.9 m/s)
** The minus sign indicates that the velocity vector points in the opposite direction with respect to the initial direction of the 77.8 kg player **
The final total momentum is equal to:
m1*v1_f + m2*v2_f = (77.8 kg)v1_f + (99.8 kg)(3.5 m/s)
The conservation of momentu tell us that:
m1v1_i + m2v2_i = m1v1_f + m2v2_f
Therefore:
v1_f =v1_i + (m2/m1)*(v2_i-v2_f)
v1_f = 8.1 m/s + (99.8 / 77.8) * (-6.9 - 3.5 m/s)
<u>v1_f = -5.24 m/s</u>
Answer:
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