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Norma-Jean [14]
3 years ago
13

In a binomial distribution, n = 12 and π = .60.

Mathematics
1 answer:
Lemur [1.5K]3 years ago
3 0

For binomial distribute we use formula

nCr (p)^r (q)^{n-r}

the probability mass function of the binomial distribution is:

nCr (\pi)^r (1-\pi)^{n-r}

Given n = 12 and π = .6. (Replace the values)

the probability for x = 5, we need to find P(x=5). Here r= 5

P(x=5)= 12C5(\pi )^5 (1-\pi)^{12-5}

= 12C5(0.6 )^5 (0.4)^{7}= 0.10090 = 0.101

(b) the probability for x ≤ 5

P(x<=5) = P(x=0) + P(x=1) +P(x=2)+ P(x=3) + P(x=4) + P(x=5)

P(x<=5) = 12C0(0.6 )^0(0.4)^{12} + 12C1(0.6 )^1(0.4)^{11} +  12C2(0.6 )^2(0.4)^{10} + 12C3(0.6 )^3(0.4)^{9} + 12C4(0.6 )^4(0.4)^{8} + 12C5(0.6 )^5 (0.4)^{7}

= 0.15821229 = 0.158

(c) find the probability for x ≥ 6

P(x>=6) =P(x=6) + P(x=7) +P(x=8)+ P(x=9) + P(x=10) + P(x=11)+ P(x=12)

P(x>=6) = 12C6(0.6 )^6(0.4)^{6} + 12C7(0.6 )^7(0.4)^{5} + 12C8(0.6 )^8(0.4)^{4} + 12C9(0.6 )^9(0.4)^{3} + 12C10(0.6 )^{10}(0.4)^{2} +   12C11(0.6 )^{11}(0.4)^{1}  +  12C12(0.6 )^{12}(0.4)^{0}

= 0.8417877 = 0.0842 (rounded to 3 decimal places)



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