Answer:
<h3>The answer is 1064.75 g</h3>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
volume of substance = 250 cm³
density = 4.259 g/cm³
We have
mass = 4.259 × 250
We have the final answer as
<h3>1064.75 g</h3>
Hope this helps you
Answer:
The actual value = 25.7 ml
The error = 15.6%
This means that the value of error = 0.156 * 25.7 = 4.0092 ml
Now, the error percentage found means that the student got the value either greater than the actual one with the value of error or less than the actual one with the value of error.
This means that the two possible readings are:
either : 25.7 + 4.0092 = 29.7092 ml
or : 25.7 - 4.0092 = 21.6908 ml
Explanation:
<h3>
Answer:</h3>
Initial temperature is 243.59°C
<h3>
Explanation:</h3>
The quantity of heat is calculated by multiplying the mass of a substance by its specific heat capacity and change in temperature.
That is; Q = m×c×ΔT
In this case;
Quantity of heat = 560 J
Mass of the Sample of Zinc = 10 g
Final temperature = 100°C
We are required to determine the initial temperature;
This can be done by replacing the known variables in the formula of finding quantity of heat,
Specific heat capacity, c, of Zinc = 0.39 J/g.°C
Therefore,
560 J = 10 g × 0.39 J/g°C × ΔT
ΔT = 560 J ÷ (3.9 J/°C)
= 143.59°C
But, since the sample of Zinc lost heat then the temperature change will have a negative value.
ΔT = -143.59°C
Then,
ΔT = T(final) - T(initial)
Therefore,
T(initial) = T(final) - ΔT
= 100°C - (-143.59°C)
= 243.59°C
Hence, the initial temperature of zinc sample is 243.59°C
C3H8 + 5O2 ------> 3CO2 + 4H2O
from reaction 1 mol 5 mol
given 1.82 mol x mol
x=(1.82*5)/1 = 9.10 mol CO2
Let's divide the three experiments: The experiment with 10.00 mL of water is A), the experiment with 15.00 mL is B), and the experiment with 25.00 mL is C).
- (1) Now let's calculate the experimental density of each experiment. Density (ρ) is equal to the mass divided by the volume, thus:
- (2)To calculate the average density, we add each density and divide the result by the number of experiments (in this case 3):
- (3) The percent error is calculated by dividing the absolute value of the substraction of the theorethical and experimental values, by the theoretical value, times 100:
%error=
%error=
%error=2.44 %
