Ideally, the resistance of an ammeter should be:

Two cars cover the same distance in a straight line. Car A covers the distance at a constant velocity. Car B starts from rest an

SpyIntel [72]

Answer:

a) 2.43 m/s

b) 4.83 m/s

c) 0.023 m/s²

Explanation:

a) Both cars cover a distance of 510 m in 210 s. Since car A has no acceleration

Speed = Distance / Time

$\text{Speed}=\frac{510}{210}=2.43\ m/s$

Velocity of car A is 2.43 m/s

t = Time taken = 210 seconds

u = Initial velocity

v = Final velocity

s = Displacement = 510 m

a = Acceleration

c)

$s=ut+\frac{1}{2}at^2\\\Rightarrow 510=0\times 210+\frac{1}{2}\times a\times 210^2\\\Rightarrow a=\frac{510\times 2}{210^2}\\\Rightarrow a=0.023\ m/s^2$

Acceleration of car B is 0.023 m/s²

b)

$v=u+at\\\Rightarrow v=0+0.023\times 210\\\Rightarrow v=4.83\ m/s$

Final velocity of car B is 4.83 m/s

6 0

3 years ago

In which direction does the magnetic field in the center of the coil point?

neonofarm [45]

left side magnetic field in the centre of the coil point

6 0

3 years ago

Jason hits volleyball so that it moves with an initial velocity of 6.0 m/s straight upward. If the volleyball starts 2.0 m above

Luda [366]

Answer: 1.497 s

Explanation:

This situation is related to projectile motion or parabolic motion, in which the initial velocity of the volleyball has only y-component, since it was hit straight upward.

Being the main equation as follows:

$y=y_{o}+V_{oy} t +\frac{gt^{2}}{2}$ (1)

Where:

$y_{o}=2 m$ is the initial height of the volleyball

$y=0$ is the final height of the volleyball (when it finally strikes the floor)

$V_{oy}=6 m/s$ is the volleyball's initial velocity

$t$ is the time the volleyball is in the air

$g=-9.8m/s^{2}$ is the acceleration due gravity (always directed downwards)

Rewritting (1) with the given conditions:

$\frac{gt^{2}}{2} + V_{oy} t + y_{o}=0$ (2)

$-\frac{9.8 m/s^{2}}{2}t^{2} + 6 m/s t + 2 m=0$

$-4.9 m/s^{2}t^{2} + 6 m/s t + 2 m=0$ (3)

This is a <u>quadratic equation</u> (also called <u>equation of the second degree</u>) of the form $at^{2}+bt+c=0$ , which can be solved with the following formula: