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Sloan [31]
3 years ago
9

A box is sliding down an incline tilted at a 16.0 angle above horizontal. The box is initially sliding down the incline at a spe

ed of 1.90 m/s. The coefficient of kinetic friction between the box and the incline is 0.420. How far does the box slide down the incline before coming to rest?
A) 2.33 m

B) 0.720 m

C) 1.78 m

D) 1.44 m

E) The box does not stop. It accelerates down the plane
Physics
1 answer:
blsea [12.9K]3 years ago
8 0

Answer:

d) 1.44m

Explanation:

According to Newton's second law:

\sum F=m.a\\

analyzing the horizontal components of the force:

\sum F_x=mg*sin(\theta)-\µ*m.g*cos(\theta)\\\sum F_x=m*9.8*(sin(16^o)-0.420*cos(16^o))\\\sum F_x=-1.25m

applying the second law

-1.25m=m.a\\a=-1.25m/s^2

given the acceleration we can calculate the distances traveled before stopping:

(v_f)^2=(v_o)^2+2.a.\Delta x\\0=(1.90m/s)^2-2(1.25)*\Delta x\\\Delta x=1.44m

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Answer:

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given,

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