All categories

3 years ago

What are the issues that hinders efforts to achieve sustainability?

Physics

1 answer:

Nadya [2.5K]3 years ago

4 0

Answer:

who will solve environmental problems, who is responsible for environmental problems, and who pays the cost of implementing solutions

Explanation:

You might be interested in

There are two equations from which a change in the gravitational potential energy u of the system of a mass m and the earth can

Colt1911 [192]

The change in the gravitational potential energy is represented by the equation
u = ΔPE = Δmgh
since the mass of the system will remain constant and the acceleration due to gravity will also remain constant, the equation will become
u = mg Δh

5 0

2 years ago

- Which of the following cannot be a unit for work? A. Joule B. N.m C. Kilowatt D. All

shusha [124]

Answer:

joule

Explanation:

is for work it is also repreasent by SI

4 0

2 years ago

Quiz

MariettaO [177]

Kinetic energy is dependent on Its position

3 0

2 years ago

If an arrow is fired from a bow with a perfectly horizontal velocity of 60.0 m/s and the arrow had a vertical velocity of 6m/s j

Delvig [45]

Answer:

t = 1,28 s

Explanation: This problem is a projectile motion problem.

V₀ₓ = V₀ * cosθ

Vₓ = constant all the way

Vₓ = V₀ₓ

tanθ = Vyi/Vxi that means in any point of the trajectory

tanθ = 6 / 60 ( just before touching the ground )

tanθ = 0,1 then arctan 0,1 ≈ 6⁰

sin 6⁰ = 0,1045

cos 6⁰ = 0,9945

V₀ₓ = V₀ * cosθ ⇒ V₀ = V₀ₓ / cosθ ⇒ V₀ = 60 / 0,9945

V₀ = 60,33 m/s

V₀y = V₀ * sin θ ⇒ V₀y = 60,33 * 0,1045 ⇒ V₀y = 6,30 m/s

Vy = V₀y - g * t

At maximum y Vy = 0 ( the middle of the trajectory)

g*tm = V₀y ⇒ tm= V₀y / g

tm = 6,30 / 9,8

tm = 0,64 s ( time to reach maximum y )

Then the time of fligh is twice 0,64 s

t = 0,64 * 2

t = 1,28 s

7 0

3 years ago

The index of refraction for red light in water is 1.331 and that for blue light is 1.340. A ray of white light enters the water

Alex Ar [27]

Answer:

(a) 47.08°

(b) 47.50°

Explanation:

Angle of incidence = 78.9°

For blue light :

Using Snell's law as:

$\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}$

Where,

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₂ is the refractive index for blue light which is 1.340

n₁ is the refractive index of air which is 1

So,

$\frac {sin\theta_2}{sin{78.9}^0}=\frac {1}{1.340}$

${sin\theta_2}=0.7323$

Angle of refraction for blue light = sin⁻¹ 0.7323 = 47.08°.

For red light :

Using Snell's law as:

$\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}$

Where,

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₂ is the refractive index for red light which is 1.331

n₁ is the refractive index of air which is 1

So,

$\frac {sin\theta_2}{sin{78.9}^0}=\frac {1}{1.331}$

${sin\theta_2}=0.7373$

Angle of refraction for red light = sin⁻¹ 0.7373 = 47.50°.

5 0

3 years ago