Answer:
0.01 C
Explanation:
Applying,
F = qvBsinФ................ Equation 1
Where F = Force on the charged particle, q = charge on the particle, v = velocity, B = magnetic field, Ф = angle
Since the charged particle noves in a circle,
F = mv²/r................. Equation 2
Where m = mass of the particle, v = velocity of the particle, r = radius of the circle
Substitute equation 2 into equation 1
mv²/r = qvBsinФ
make q the subject of the equation
q = mv/(rBsinФ)............. Equation 3
Given: m = 0.005 kg, v = 2 m/s, r = 0.2 m, B = 5 T, Ф = 90° (Act at right angle)
Substitute these values into equation 3
q = (0.005×2)/(0.2×5×sin90°)
q = 0.01/(1)
q = 0.01 C
