During circular motion, the force that is perpendicular to the velocity and toward the center of the circle is the ... ?
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Answer:
300N
Explanation:
Given parameters:
Mass of car = 1500kg
Initial velocity = 0m/s
Distance covered = 45m
Time = 15s
Unknown:
Net force applied = ?
Solution:
From Newton's second law:
Force = mass x acceleration
Force = mass x
v is the final velocity
u is the initial velocity
t is the time taken
Final velocity = =3m/s
Force = 1500 x = 300N
Answer:
ρ = 1.6*10⁻⁸ Ω/m.
Explanation:
- Applying Ohm's Law to the wire, assuming that it can be treated as a pure resistance, the resistance of the wire can be obtained as follows:
- At the same time, we know that there exists a relationship between the resistance, the resistivity ρ, the length L and the area A of the wire, that is given for the following expression:
- The area of the circular section of the wire, can be expressed as a function of the diameter d, as follows:
- Replacing the left side of (2) by (1), and (3) on the right side, we can solve for the resistivity ρ as follows:
- ρ = 1.6*10⁻⁸ Ω/m
Answer:
R=0.5B+0.5C+2A+D
Explanation:
By the triangular law of vector addition
vector R= vector B- vector D
As A,B,C,D are edges of the parallelogram,
A is parallel to D but opposite in direction.
Therefore
;
;
B is parallel to C and in same direction.