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lidiya [134]
4 years ago
12

During circular motion, the force that is perpendicular to the velocity and toward the center of the circle is the ... ?

Physics
1 answer:
Ivanshal [37]4 years ago
5 0
That's the "centripetal" force.  It produces the centripetal acceleration
that pulls the object away from a straight path into a bent path.
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Heat is transferred from your body into an ice cube by
Dima020 [189]
2.) <span>Heat is transferred from your body into an ice cube by "Conduction"

3.) </span><span>The loudness of a sound will be determined by the wave’s "Frequency"

4.) </span>The speed of a sound wave <span>"is slower than an electromagnetic wave"

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3 0
3 years ago
A 1500kg car is at rest before it accelerates when the light turns green. If it covers 45.0 meters in 15.0 seconds, what is the
lana [24]

Answer:

300N

Explanation:

Given parameters:

Mass of car  = 1500kg

Initial velocity  = 0m/s

Distance covered  = 45m

Time  = 15s

Unknown:

Net force applied  = ?

Solution:

From Newton's second law:

  Force  = mass x acceleration

  Force  = mass x \frac{v - u}{t}  

v is the final velocity

u is the initial velocity

t is the time taken

    Final velocity  = \frac{45}{15}   =3m/s

 Force  = 1500 x \frac{3 - 0}{15}   = 300N

8 0
3 years ago
A wire 50.0 m long and 2.00 mm in diameter is connected to a source with a potential difference of 9.11 V, and the current is fo
Alex787 [66]

Answer:

ρ = 1.6*10⁻⁸ Ω/m.

Explanation:

  • Applying Ohm's Law to the wire, assuming that it can be treated as a pure resistance, the resistance of the wire can be obtained as follows:

       R = \frac{V}{I} = \frac{9.11V}{36.0A} = 0.253  \Omega (1)

  • At the same time, we know that there exists a relationship between the resistance, the resistivity ρ, the length L and the area A of the wire, that is given for the following expression:

       R = \rho* \frac{L}{A} (2)

  • The area of the circular section of the wire, can be expressed as a function of the diameter d, as follows:

      A = \frac{\pi*d^{2} }{4} = \frac{\pi*(0.002m)^{2}}{4} = \pi*10e-6 (3)

  • Replacing  the left side of (2) by (1), and (3) on the right side, we can solve for the resistivity ρ as follows:

       \rho = \frac{R*A}{L} = \frac{0.253\Omega*\pi*10e-6}{50.0m} = 1.6e-8 \Omega/m

  • ρ = 1.6*10⁻⁸ Ω/m
4 0
3 years ago
Express the vector R<br> B<br> in terms of A, B, C, and Ď, the edges of a<br> parallelogram.
Vadim26 [7]

Answer:

R=0.5B+0.5C+2A+D

Explanation:

By the triangular law of vector addition

vector R= vector B- vector D

As A,B,C,D are edges of the parallelogram,

A is parallel to D but opposite in direction.

Therefore

A = (-D);A//D;

2A=-2D

B is parallel to C and in same direction.

B//C\\B=C\\

0.5B=0.5C\\

R= B-D;\\R= 0.5B+0.5B-D;\\R=0.5B+0.5C-D;\\R=0.5B+0.5C-2D+D;\\R=0.5B+0.5C+2A+D;

7 0
3 years ago
Hello
AysviL [449]

Answer:

The wind will blow from the higher pressure over the water to lower pressure over the land causing the sea breeze. The sea breeze strength will vary depending on the temperature difference between the land and the ocean. At night, the roles reverse. The air over the ocean is now warmer than the air over the land.

Sea breezes occur during hot, summer days because of the unequal heating rates of land and water. During the day, the land surface heats up faster than the water surface. Therefore, the air above the land is warmer than the air above the ocean. Now, recall that warmer air is lighter than cooler air.

4 0
4 years ago
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