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Nuetrik [128]
3 years ago
8

A hockey player swings her hockey stick and strikes a puck. According to Newtons 3rd law of motion which of the following is a r

eaction to the stick pushing on the puck
Physics
1 answer:
Korvikt [17]3 years ago
3 0

<u>Complete Question:</u>

A hockey player swings her hockey stick and strikes a puck. According to Newton’s third law of motion, which of the following is a reaction to the stick pushing on the puck?

A. the puck pushing on the stick .

B. the stick pushing on the player .

C. the player pushing on the stick .

D. the puck pushing on the player.

<u>Correct Option:</u>

According to Newton’s third law of motion the puck pushing on the stick is a reaction to the stick pushing on the puck.

<u>Option: A</u>

<u>Explanation:</u>

As when the hockey exert force on the puck (which is a flat ball basically used in ice hockey) then this action by hockey will receive equal and opposite reaction by puck. Thus when the stick is pushing on the this flat ball, then puck also push the stick. This is understood by newton's third law pf motion, where action and reaction forces are subject of discussion, displaying their is pair of forces applied among the interacting objects. This form is observed more practically in life and very frequent.

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Answer:

ratio = 1 : 4.5

Explanation:

If m₁ is the mass of the star and m₂ the mass of the planet, the force of gravity F₁ for planet 1 is given by:

F_1=\frac{Gm_1m_2}{r^2}

The force F₂:

F_2=\frac{Gm_1(2m_2)}{(3r)^2}

The ratio:

\frac{F_2}{F_1}=\frac{2}{9}

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3 years ago
An iron railroad rail is 800 ft long when the temperature is 31°C. What is its length (in ft) when the temperature is −17°C?
natta225 [31]

Answer:

799.54 ft

Explanation:

Linear thermal expansion is:

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where ΔL is the change in length,

α is the linear thermal expansion coefficient,

L₀ is the original length,

and ΔT is the change in temperature.

Given:

α = 1.2×10⁻⁵ / °C

L₀ = 800 ft

ΔT = -17°C − 31°C = -48°C

Find: ΔL

ΔL = (1.2×10⁻⁵ / °C) (800 ft) (-48°C)

ΔL = -0.4608

Rounded to two significant figures, the change in length is -0.46 ft.

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A tennis ball connected to a string is spun around in a vertical, circular path at a uniform speed. The ball has a mass m = 0.16
ycow [4]
We assign the variables: T as tension  and x the angle of the string
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<span>(4)We have T=(0.163v²)/0.9 – 0.163x9.8cosx.

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4 0
3 years ago
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Ludmilka [50]

Answer:

ΔP.E = 6.48 x 10⁸ J

Explanation:

First we need to calculate the acceleration due to gravity on the surface of moon:

g = GM/R²

where,

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Therefore,

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g = 2.82 m/s²

now the change in gravitational potential energy of rocket is calculated by:

ΔP.E = mgΔh

where,

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Therefore,

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Tems11 [23]

Answer:

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Rounded to two significant figures, the man must run with a speed of 5.3 m/s.

3 0
3 years ago
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