Answer:
Acceleration of the box is 4.9 m/s².
Explanation:
The free body diagram is shown below.
The weight of the body can be resolved into two mutually perpendicular components as shown. The force responsible for sliding motion of the box along the incline is due to
acting along the incline.
Therefore, as per Newton's second law of motion,
Net force = 
Now, net force acting along the incline is only 
Therefore,

Now, 
Therefore, the acceleration of the box is given as:

Acceleration of the box is 4.9 m/s².
Answer:
98 N
Explanation:
The weight of an object is given by:

where
m is the mass of the object
is the acceleration due to gravity
In this problem, the mass of the lemur is m=10 kg, so its weight is

solution:
Using Cartesian co-ordinate system
Final velocity =v= -4m/s
Initial velocity = u
Acceleration a = m/s²
Time (t).= 60s
By the first kinematical equation
V= u +at
U = v – at
=(-4)-(-3)(60)
176m/s
So, initial velocity was 176m/s