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MrMuchimi
3 years ago
8

A backpack has a mass of 8 kg. It is lifted and given 54.9 J of gravitational potential energy. How high is it lifted?

Physics
2 answers:
zlopas [31]3 years ago
5 0
M=4kg
Eg=54,9J
g≈9,8m/s²

h=?

Eg=m*g*h
h=Eg/(m*g)=54,9J/(8kg*10m/s²)≈0,7m

answer: A




"Non nobis Domine, non nobis, sed Nomine tuo da gloriam."



Regards M.Y.

tresset_1 [31]3 years ago
3 0

Answer:

0.7 m like the other person said and explained :))

Explanation:

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Luda [366]

The kilogram is the SI unit of mass and it is the almost universally used standard mass unit. The associated SI unit of force and weight is the Newton, with 1 kilogram weighing 9.8 Newtons under standard conditions on the Earth's surface.

6 0
3 years ago
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The equation y = 5 Sin (3x - 4t), where
igomit [66]

Answer:

Frequency, f = 0.63 Hz

Period, T = 1.58 s

Speed of a wave, v = 1.34 m/s

Explanation:

The equation of a wave is given by :

y = 5 \sin (3x - 4t) ...(1)

y is in mm

x is in meters

t is in seconds

The general equation of a wave is given by :

y=A\sin(kx-\omega t) ...(2)

(i) Compare equation (1) and (2) we get :

k=3\\\\\omega=4

Since,

\omega=2\pi f\\\\f=\dfrac{\omega}{2\pi}\\\\f=\dfrac{4}{2\pi}\\\\f=0.63\ Hz

(ii) Period of wave is :

T=\dfrac{1}{f}\\\\T=\dfrac{1}{0.63}\\\\T=1.58\ s

(iii) Speed of a wave,

v=\dfrac{\omega}{k}\\\\v=\dfrac{4}{3}\\\\v=1.34\ m/s

4 0
3 years ago
Find the deBroglie wavelength of an electron with 4.0 eV.
pantera1 [17]

Explanation:

It is given that,

Voltage, V=4 eV=4\times 1.6\times 10^{-19}\ V= 6.4\times 10^{-19}\ V

De broglie wavelength in terms of voltage is given by :

\lambda=\dfrac{h}{\sqrt{2meV} }

m and e are the mass and charge on electron. So,

\lambda=\dfrac{12.27}{\sqrt{V} }\ A

\lambda=\dfrac{12.27}{\sqrt{6.4\times 10^{-19}} }\ A  

\lambda=1.53\times 10^{10}\ A

\lambda=1.53\ m

So, the De broglie wavelength of an electron is 1.53 meters. Hence, this is the required solution.      

3 0
3 years ago
Red light of wavelength 630 nm passes through two slits and then onto a screen that is 1.3 m from the slits. The center of the 3
frozen [14]

Answer:

a) f = 4.76 10¹⁴ Hz, b) d = 2.73 10⁻⁴ m, c) θ = 6.923 10⁻³ rad

Explanation:

a) In this problem the frequency of light is asked, let's use the relationship between the speed of the wave, its wavelength and its frequency

           c = λ f

           f = c /λ

           f = \frac{3 \ 10^8}{630 \ 10^{-9}}

           f = 4.76 10¹⁴ Hz

b) slit separation (d)

the expression for the constructive interference of the double-slit experiment is

          d sin  θ = m λ

let's use trigonometry

          tan θ = y / L

          tan θ = \frac{sin \theta}{cos \theta}

in general the angles are small, so we can approximate

          tan θ = sin θ

          tan θ = y/L

we substitute

          d y / L = m λ

          d = m L λ / y

we calculate

          d = 3  1.3  630 10⁻⁹ /0.90 10⁻²

          d = 2.73 10⁻⁴ m

c) the angle

           tan θ = y / L

           θ = tan⁻¹ y / L

           θ = tan⁻¹ 0.9 10⁻² / 1.3

           θ = tan⁻¹ 6,923 10⁻³

let's find the angle in radians

           θ = 6.923 10⁻³ rad

   

4 0
3 years ago
Review. A rechargeable battery of mass 15.0 g delivers an average current of 18.0 mA to a portable DVD player at 1.60 V for 2.40
xenn [34]

The internal energy produced in the battery during one charge-discharge cycle is 7.8 J.

<h3>What is the energy?</h3>

Energy is defined as the ability to do work. Now we can tell about the energy of the charge from the information provide;

Mass of the battery = 15.0 g

Current = 18.0 mA

Voltage =  1.60 V

Time (t1) =  2.40 h

Time (t2) = 4.2 h

Recall that internal energy = energy of the charge = 2.3 * 1.8 * 10^-2 * 4.2 * 60 = 7.8 J

Hence the internal energy produced in the battery during one charge-discharge cycle is 7.8 J.

Learn more about rechargeable battery:brainly.com/question/27894283

#SPJ4

5 0
2 years ago
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