Terminal velocity.................................................................................
Answer:
12.974 m/s
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
g = Acceleration due to gravity = 9.81 m/s²
= Coefficient of friction =0.66
a = Acceleration = ![\mu g](https://tex.z-dn.net/?f=%5Cmu%20g)
![v^2-u^2=2as\\\Rightarrow -u^2=2\mu gs-v^2\\\Rightarrow u=\sqrt{v^2-2\mu gs}\\\Rightarrow u=\sqrt{0^2-2\times -(9.81\times 0.66)\times 13}\\\Rightarrow u=12.974\ m/s](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as%5C%5C%5CRightarrow%20-u%5E2%3D2%5Cmu%20gs-v%5E2%5C%5C%5CRightarrow%20u%3D%5Csqrt%7Bv%5E2-2%5Cmu%20gs%7D%5C%5C%5CRightarrow%20u%3D%5Csqrt%7B0%5E2-2%5Ctimes%20-%289.81%5Ctimes%200.66%29%5Ctimes%2013%7D%5C%5C%5CRightarrow%20u%3D12.974%5C%20m%2Fs)
Car's original speed before braking was 12.974 m/s
1 angstrom = 10^-8 cm
6.5 x 10-4 cm = 65 000 x 10-8 cm = 65 000 angstroms
answer 65 000 angstroms
Explanation:
Check out the picture I drew for a minute before reading this...
B. Distance [the red line] is a scalar quantity reflecting how far an object has traveled. Displacement [the green line] is a vector quantity reflecting how far an object has moved from a point. The key difference is that distance can be any sort of path while displacement is always a vector (or a straight line) between a starting point and a finishing point. Sometimes distance and displacement are equal to one another. Sometimes you have a distance traveled, but zero displacement overall; which is what's going on in your question.
A. The distance that the racecar traveled is indeed 500m. But at the end of the lap, it is right back where it started. So overall, it has been displaced 0m.
Answer:
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Explanation:
UK is a very popular and most popular film with all its history of the vessel and the video will will certainly help me in this way and the rest will not even hold any more in their head with their own or their own home or home