It’s hay, most farmers have their livestock eat hay and grass
The question is incomplete. The complete question is :
Two loudspeakers are placed 1.8 m apart. They play tones of equal frequency. If you stand 3.0 m in front of the speakers, and exactly between them, you hear a minimum of intensity. As you walk parallel to the plane of the speakers, staying 3.0 m away, the sound intensity increases until reaching a maximum when you are directly in front of one of the speakers. The speed of sound in the room is 340 m/s.
What is the frequency of the sound?
Solution :
Given :
The distance between the two loud speakers, 
The speaker are in phase and so the path difference is zero constructive interference occurs.
At the point 
, the speakers are out of phase and so the path difference is 
Therefore,
Thus the frequency is :
Hz
Answer: Option (c) is the correct answer
Explanation:
It is known that when a neutral object comes in contact with a charged object then an opposite charge develops on the neutral object. But this development of charge occurs only when both the objects come in contact and if they are not in contact with each other then there occurs no charge on the neutral object.
As in the given situation, negatively-charged glass rod is brought near, but does not touch the sphere. So, there will occur no charge on the sphere.
Thus, we can conclude that final charge on the sphere is neutral.
<h2>The option ( b ) is appropriate answer </h2>
Explanation:
When a projectile is projected from height horizontally . The only force acting upon it is the downwards gravitational force of attraction due to earth .
Due to this force its vertical component of velocity , which is in the downward direction will be increased .
As there is no force horizontally , the horizontal velocity of throw will remain constant .
Thus ( b ) option is the correct option .
